<u>ANSWER</u>
It is not one-to-one function
<u>EXPLANATION</u>
A one-to-one function must pass the horizontal line test.
The graph described in the question looks like the one in the attachment.
A horizontal line drawn in red cuts the graph at more than one point.
Therefore the parabola shown facing up with a vertex 
is not a one-to-one function.
Nice, already in vertex form
y=a(x-h)^2+k
(h,k) is vertex
therfor since (-3,6) is vertex
we are looking for something like
y=a(x-(-3))^2+6 simplified to
y=a(x+3)^2+6
A is ansre
Answer: 6i) 6a² - 2ab
6ii) -2b³
6iii) b³ + 7b² - 49b
<u>Step-by-step explanation:</u>
6i) (a + b)(5a - 3b) + (a - 3b)(a - b)
= 5a² - 3ab + 5ab - 3b² + a² - ab - 3ab + 3b²
= 5a² + 2ab - 3b² + a² - 4ab + 3b²
= 6a² - 2ab
6ii) (a - b)(a² + b² + ab) - (a + b)(a² + b² - ab)
= a³ + ab² + a²b - ab² - a²b - b³ - (a³ + ab² - a²b -ab² + a²b + b³)
= a³ - b³ - (a³ + b³)
= a³ - b³ - a³ - b³
= -2b³
6iii) (b² - 49)(b + 7) + 343
= b³ + 7b² - 49b - 343 + 343
= b³ + 7b² - 49b
You are allowed a maximum of 3 questions.
Please post #7 on a different question.
Answer:
y = (1/2)x + 1
Step-by-step explanation:
linear line equation is y = mx + b
Where m is the slope and b is the y-intercept when x is 0.
For m, m is change in y(delta y) over change in x(delta x).
We are given two points: (0,1) and (4,3).
m = (y2 - y1)/(x2 - x1) = (3-1)/(4-0) = 2/4 = 1/2
y = (1/2)x + b
Now plug in (0,1) into above equation to find b value.
1 = (1/2)0 + b => b = 1
Final equation is y = (1/2)x + 1
