Answer:
<em>0.228 nm</em>
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Explanation:
Atomic mass number of copper = 64
but an atomic mass unit = 1.66 x 10^-27 kg
therefore, the mass of the copper atom m = 64 x 1.66 x 10^-27 kg = 1.06 x 10^-25 kg
The number of atoms in this mass n = ρ/m
where ρ is the density of copper = 8.96 x 10^3 kg/m^3
==> n = (8.96 x 10^3)/(1.06 x 10^-25) = 8.45 x 10^28 atoms/m^3
We know that the volume occupied by this amount of atoms n = 
where a is the lattice constant
equating, we have
8.45 x 10^28 =
a = 4.389 x 10^9
we also know that
d = 1/a
where d is the smallest distance between the two copper atom.
d = 1/(4.389 x 10^9) = 2.28 x 10^-10 m
==> <em>0.228 nm</em>
Given :
You fire a paintball from a paintball gun straight up into the air at 25.0 m/s.
To Find :
What is the ball velocity at the higher point that the ball reaches.
Solution :
We know, when ball is moving upward acceleration due to gravity is applied downward.
So, the ball will decelerate and when ball reaches maximum height its velocity will become zero.
Therefore, ball velocity is 0 m/s at maximum height.
Hence, this is the required solution.
Answer:
C.) v = 50 m/s
Explanation:
The relationship between position vs. time graph and velocity is that the derivative (slope) of the position vs. time graph gives you velocity. In other words, find the slope to get the velocity.
Select two arbitrary points. I'll choose (3s, 225m) and (0s, 75m).
Now use the slope equation:
v = 50 m/s
Hopes this helps!
Answer:
1) when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water
2) sulfur dioxide and nitrogen oxides
3)mixtures of sodium bicarbonate,magnesium hydroxide, calcium carbonate
4)
A) sulfuric acid
B) calcium ammonium nitrate
C) calcimine, kalsomine, calsomine, or lime paint
D) ammonium hydroxide
5)
A) Na2SO4 + H2O
B) NaCl + H2O + CO2
6) I can't find anything to help with the answers
7)
A) Can't find any thing
B) copper oxide
Answer:
A.No. Assuming no other factors (such as air resistance) the first object will have a velocity of 32 feet/second when the other is dropped. Since they will both have the same acceleration, the first distance between them will increase by 32 feet per second.
Explanation:
