Answer:
1.13 × 10⁶ g
Explanation:
Let's consider the reduction of aluminum (III) from Al₂O₃ to pure aluminum.
Al³⁺ + 3 e⁻ → Al
We can establish the following relations:
- 1 Ampere = 1 Coulomb / second
- The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
- 1 mole of Al is produced when 3 moles of electrons circulate
- The molar mass of Al is 26.98 g/mol.
The mass of aluminum produced under these conditions is:
Answer:
AINO3 - 89 g/mol
Explanation:
Molar mass of a compound or molecule is obtained by summing the individual atomic masses of the elements that makes the compound.
In this question, the elements are Al, N and O
The molar mass is given as;
Molar mass = Al + N + 3 (O)
Al = 27
N = 14
O = 16
Molar mass = 27 + 14 + 3(16)
Molar mass = 89 g/mol
Answer:
137
Explanation:
6.022x1023 is one mole. to work out the mass you do number of moles multiplied my Mr (which is 137)
1 mole x 137 = 137g
Answer:
Mass = 42 kg
Volume = 2 m^3
By using formula = Density = Mass/Volume
= 42/2
= 21/1
= 21
= 21 m^3
Answer:
will be the speed in 
Explanation:
This is a unit conversion problem.
To solve it, we need the equivalences between km and ft, ft and mi and hr and s.
The equivalences are :
If 
then
The trick is to multiply by one the speed given until to convert it in mi/s units
Notice that km,ft,hr and min have been cancelled.
Be careful of the fraction order.
Multiply by ft/km is different that multiply by km/ft
