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3 years ago

How can solubility help you identify a substance

1 answer:

5 0

The solubility of a substance is usually expressed as the mass of a substance, in g, that will dissolve in a fixed amount of solvent (liquid), usually 100 g, at a given temperature.

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The second-order rate constants for the reaction of oxygen atoms witharomatic hydrocarbons have been measured (R. Atkinson and J

Pepsi [2]

Answer:

A = 1,13x10¹⁰

Ea = 16,7 kJ/mol

Explanation:

Using Arrhenius law:

ln k = -Ea/R × 1/T + ln(A)

You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).

Using the values you will obtain:

y = -2006,9 x +23,147

As R = 8,314472x10⁻³ kJ/molK:

-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹

Ea = 16,7 kJ/mol

Pre-exponential factor is:

ln A = 23,147

A = e^23,147

A = 1,13x10¹⁰

I hope it helps!

6 0

3 years ago

Sodium (Na) is in Group 1 of the periodic table. Sodium atoms readily form bonds with other atoms. Which statement best explains

kramer

Answer:

Explanation:

3 0

3 years ago

Calculate the pH of a solution that is 0.235M benzoic acid and 0.130M sodium benzoate, a salt whose anion is the conjugate base

lesantik [10]

Hello!

We have the following data:

ps: we apply Ka in benzoic acid to the solution.

[acid] = 0.235 M (mol/L)

[salt] = 0.130 M (mol/L)

pKa (acetic acid buffer) =?

pH of a buffer =?

Let us first find pKa of benzoic acid, knowing that Ka (benzoic acid) = $6.20*10^{-5}$

So:

$pKa = - log\:(Ka)$

$pKa = - log\:(6.20*10^{-5})$

$pKa = 5 - log\:6.20$

$pKa = 5 - 0.79$

$\boxed{pKa = 4.21}$

Now, using the abovementioned data for the pH formula of a buffer solution or (Henderson-Hasselbalch equation), we have:

$pH = pKa + log\:\dfrac{[salt]}{[acid]}$

$pH = 4.21 + log\:\dfrac{0.130}{0.235}$

$pH = 4.21 + log\:0.55$

$pH = 4.21 + (-0.26)$

$pH = 4.21 - 0.26$

$\boxed{\boxed{pH = 3.95}}\end{array}}\qquad\checkmark$

Note:. The pH <7, then we have an acidic solution.

I Hope this helps, greetings ... DexteR! =)

8 0

3 years ago

Freon, a very useful refrigerant, is produced in the following reaction:

Svetach [21]

Answer:

The chemistry will need 2*10⁶ moles of antimony trifluoride.

Explanation:

The balanced reaction is:

3 CCl₄ (g) + 2 SbF₃ (s) → 3 CCl₂F₂(g) + 2 SbCl₃ (s)

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

CCl₄: 3 moles
SbF₃: 2 moles
CCl₂F₂: 3 moles
SbCl₃: 2 moles

You can apply the following rule of three: if by reaction stoichiometry 3 moles of freon are produced by 2 moles of antimony trifluoride, 3*10⁶ moles of Freon are produced from how many moles of antimony trifluoride?

$moles of antimony trifluoride=\frac{3*10^{6} moles of freon*2 moles of antimony trifluoride}{3 moles of freon}$

moles of antimony trifluoride= 2*10⁶

The chemistry will need 2*10⁶ moles of antimony trifluoride.

8 0

3 years ago

Conclusion

Natalija [7]

whats the question?

8 0

3 years ago