All categories

3 years ago

How can solubility help you identify a substance

1 answer:

5 0

The solubility of a substance is usually expressed as the mass of a substance, in g, that will dissolve in a fixed amount of solvent (liquid), usually 100 g, at a given temperature.

You might be interested in

Name the following bases -Ba(OH)2 - Ca(OH)2 -RbOH

Harman [31]

$Ba(OH)_2\rightarrow \bold{\green{Barium\: hydroxide}}$

$Ca(OH)_2\rightarrow \bold{\red{Calcium\: hydroxide}}$

$RbOH \rightarrow \bold{\blue{Rubidium \:hydroxide}}$

3 0

2 years ago

Read 2 more answers

Which of the following would be useful to show the growth rate of plants at varying temperatures? A. circle graph B. bar graph C

Pepsi [2]

Answer: Im thinking the answer Is B) Bar graph?

Explanation:

7 0

3 years ago

Read 2 more answers

The electron dot structure for CI is

finlep [7]

The correct option is C.
A Lewis dot diagram is a representation of the valence electron of an atom, which uses dot around the symbol of the atom. Chlorine has seven electrons in its outermost shell, these seven electrons are arranged in form of dot around the atom of chlorine. If you count the number of dot given in option C, you will notice that they are seven.

6 0

2 years ago

Read 2 more answers

How do countries with different currencies trade goods with each other?

8090 [49]

Answer:

D- They use the exchange rate to convert one's Country's currency to another's

Explanation:

6 0

2 years ago

This question has multiple parts. Work all the parts to get the most points. An aqueous antifreeze solution is 39.0% ethylene gl

nlexa [21]

Answer:

Molality = 10.300 m

Molarity = 6.5970 M

mole fraction = 0.156549

Explanation:

39.0 % = ethylene glycol

61.0 % = water

imagine the total mass = 100g

39.0% ethylene glycol = 39g

61.0 % water = 61g

1) Molality = number of moles / mass of solvent (kg)

Molar mass of ethylene glycol = 62.07g/mole

mole = 39g / 62.07g/mole = 0.6283 moles

Molality = moles / mass of solvent = 0.6283 moles / 0.061kg = 10.300 m

2) Molarity = number of moles / volume of solution

Since we know the density of the solution = 1.05g /ml

⇒ volume = 100g / 1.05g /mL = 95.24 mL = 0.09524 L

Molarity = 0.6283 moles / 0.09524 L = 6.5970 M

3) Mole fraction

moles water = 61g / 18.02g/mole = 3.38513 moles

Total number of moles = moles of ethylene glycol + moles of water = 0.6283 + 3.38513 = 4.0134276 moles

Mole fraction = 0.6283/ 4.0134276 = 0.156549

3 0

2 years ago