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yulyashka [42]
3 years ago
10

The products of a combustion reaction do NOT include ____. (1 point) water carbon dioxide carbon monoxide hydrogen The products

of a combustion reaction do NOT include Hydrogen.
Chemistry
2 answers:
nalin [4]3 years ago
7 0

the answer is water

Hope this help1

Allushta [10]3 years ago
6 0

Answer: Option (d) is the correct answer.

Explanation:

In combustion reaction, a compound reacts with oxygen and results in the formation of carbondioxide and water.

For example, when propane reacts with oxygen it results in the formation of carbondioxide and water.

The reaction is as follows.

      C_{3}H_{8} + O_{2} \rightarrow CO_{2} + H_{2}O

Also, when there is incomplete combustion of carbon then it results in the formation of carbon monoxide. This reaction is as follows.

         C + \frac{1}{2}O_{2} \rightarrow CO

Thus, we can conclude that the products of a combustion reaction do NOT include hydrogen.

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Clouds are formed by the ________ water
tatuchka [14]
Clouds are made of water. When water evaporates it turns into clouds. So, I think the answer is EVAPORATED water.
4 0
3 years ago
which statement best describes the equation caco3 2hcl → cacl2 co2 h2o? caco3 is a reactant; it is present before the reaction o
fomenos

Answer: CaCO_3 is a reactant; it is present before the reaction occurs.

Explanation:

In a chemical reaction the chemical formulas written before the arrow are described as reactants as they react together to form products which are written after the arrow.

CaCO_3 + 2HCl \rightarrow CaCl_2 + CO_2 + H_2O

Thus CaCO_3 and HCl are reactants here whereas CO_2, CaCl_2 and H_2O are products.

7 0
3 years ago
Read 2 more answers
What’s the difference between an ester and an amide
Rufina [12.5K]

In amides, the carbonyl carbon is bonded to a nitrogen. The nitrogen in an amide can be bonded either to hydrogens, to carbons, or to both. ... Another way of thinking of an ester is that it is a carbonyl bonded to an alcohol. Thioesters are similar to esters, except a sulfur is in place of the oxygen.

8 0
3 years ago
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
2 years ago
Predict the product of this chemical equation. please explain how u did it. Do not balance after finding answer.
Oksanka [162]

Answer:

The products are CO₂ and H₂O.

The ballanced equation is this:

2C₄H₆ + 11O₂  →   8CO₂  +   6H₂O

Explanation:

In any chemical reaction, where you see that you have a compound reacting only with oxygen (O₂), you are in front of combustion.

Products in combustion are always water vapor and carbon dioxide.

Take a look to the methane combustion.

CH₄  +  2O₂  →  CO₂  +  2H₂O

1 mol of methane reacts with 2 moles of oxygen to form 1 mol of CO₂ and 2 moles of water.

This is the combustion for an alkene where 2 moles of the alkene reacts with 11 moles of oxygen to make water and CO₂ like this:

2C₄H₆ + 11O₂  →   8CO₂  +   6H₂O

8 0
3 years ago
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