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Luba_88 [7]
3 years ago
7

In 1909, Ernest Rutherford performed an experiment to explore the atomic structure. In his experiment, he projected high-speed α

‎ particles onto a thin gold foil. He found that all α‎ particles did not follow the same path. Most of the particles passed through the foil without any scattering, implying that most of the space in an atom is empty. Some particles were scattered at a large angle, and very few of them scattered back in the direction from which they had come. Based on these observations, Rutherford proposed an atomic model, which is known as Rutherford’s atomic model.
O True
O False
Chemistry
1 answer:
xz_007 [3.2K]3 years ago
6 0

Answer:

True

Explanation:

In 1909 Ernest Rutherford proposed to Geiger and Marsden to conduct an experiment in which they would have to launch alpha particles from a radioactive source against a gold foil a few atoms thick.

The aim of the experiment was to corroborate Rutherford's idea that the particles would pass through the metal foil with little deviation.

Rutherford's interpretation of the experimental results gave rise to a new atomic model, and concluded that the mass of the atom was concentrated in a small region of positive charges that impeded the passage of alpha particles. He suggested a new model in which the atom had a nucleus or center in which the mass and the positive charge are concentrated, and that in the extra nuclear zone are the negatively charged electrons.

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How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 6.46 atm and 45°C in the reaction shown below?
ankoles [38]
The chemical reaction equation for this is 

XeF6 + 3H2 ---> Xe + 6HF

Assuming gas behaves ideally, we use the ideal gas formula to solve for number of moles H2 with T = 318.15K (45C), P = 6.46 atm, V = 0.579L. Then we use the gas constant R = 0.08206 L atm K-1 mol-1.

we get n = 0.1433 moles H2

to get the mass of XeF6, 

we divide 0.1433 moles H2 by 3 since 1 mole XeF6 needs 3 moles H2 to react then multiply by the molecular weight of XeF6 which is 245.28 g/mole XeF6.

0.1433 moles H2 x \frac{1 mole XeF6}{3 moles H2} x \frac{245.28 g XeF6}{1 mole XeF6} = 11.71 g XeF6

Therefore, 11.71 g of XeF6 is needed to completely react with 0.579 L of Hydrogen gas at 45 degrees Celcius and 6.46 atm.
3 0
3 years ago
What are abiotic factors of the ecosystem​
dalvyx [7]

Answer:

Abiotic factors are the non-living components of the ecosystem, including its chemical and physical factors.

<em><u>Hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u>.</u></em>

7 0
3 years ago
Read 2 more answers
The distance between the nuclei of two iron atoms is about 4 angstroms.a. Trueb. False
vladimir2022 [97]

Answer:

The correct option is b. false

Explanation:

The distance between the nucleus of an atom and it's outermost shell is called is atomic radius. The atomic radius of an Iron atom (Fe) is 0.126 nm or 1.26 angstrom. The distance between the nuclei of two Iron atoms will be 1.26 × 2 = 2.52 angstroms.

Since 2.52 angstroms is lower than 4 angstroms, the correct option is false

8 0
3 years ago
Inside an atom, which of these occupies the maximum volume? a) the electrons b) the protons c) the neutrons d) empty space (vacu
icang [17]

Answer: Electrons

Explanation:The electron itself is small but it takes space as much as an atom by circling around the nucleus.

3 0
3 years ago
If 600.0 ml of air at 20.0 c is heated to 60.0L , what will be its volume
Deffense [45]
P1v1/t1 = p2t2/t2

p is constant
v1=600, t1 =20c=293K
v2=?, t2=60c=333K
temperature must be in Kelvin

do the math
5 0
3 years ago
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