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Luba_88 [7]
3 years ago
7

In 1909, Ernest Rutherford performed an experiment to explore the atomic structure. In his experiment, he projected high-speed α

‎ particles onto a thin gold foil. He found that all α‎ particles did not follow the same path. Most of the particles passed through the foil without any scattering, implying that most of the space in an atom is empty. Some particles were scattered at a large angle, and very few of them scattered back in the direction from which they had come. Based on these observations, Rutherford proposed an atomic model, which is known as Rutherford’s atomic model.
O True
O False
Chemistry
1 answer:
xz_007 [3.2K]3 years ago
6 0

Answer:

True

Explanation:

In 1909 Ernest Rutherford proposed to Geiger and Marsden to conduct an experiment in which they would have to launch alpha particles from a radioactive source against a gold foil a few atoms thick.

The aim of the experiment was to corroborate Rutherford's idea that the particles would pass through the metal foil with little deviation.

Rutherford's interpretation of the experimental results gave rise to a new atomic model, and concluded that the mass of the atom was concentrated in a small region of positive charges that impeded the passage of alpha particles. He suggested a new model in which the atom had a nucleus or center in which the mass and the positive charge are concentrated, and that in the extra nuclear zone are the negatively charged electrons.

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Describe and explain how petrol is separated from the mixture of hydrocarbons in crude oil.
lara31 [8.8K]
The crude oil is heated in a process of fractional distillation (note: you can research this online if you require more detail) and this process causes different hydrocarbons to condense at different heights up the distillation column. They will therefore run down the side of the column and into different areas depending on their boiling point.
7 0
4 years ago
A 1.200 liter solution contains 35.0 grams of potassium iodide (KI). What is the molarity of this
enot [183]

Answer:

M = 0.177

Explanation:

First, we have to find the molar mass of potassium iodine (KI).

K = 39.098

I = 126.904

Now, add these values together to get the molar mass of KI

39.098 + 126.904 = 166.0028

Now, it's time to do a grams to moles conversion.

35.0 g KI * \frac{1 mol KI}{166.0028 g KI} = \frac{35.0}{166.0028} = 0.212 mol KI

Now, we can find the molarity of this solution.

Molarity (M) = \frac{mol}{L}

M = \frac{0.212 mol KI}{1.200 L} = 0.177 M

The molarity (M) of this solution is 0.177.

3 0
4 years ago
Where does precipitation occur in the water cycle?
timofeeve [1]
Ahead of a warm front.
7 0
4 years ago
Read 2 more answers
2. What ions are present in what ratio in a solution of aqueous calcium chloride?
Alenkasestr [34]

Answer:

\mathrm{Ca}^{2+} \text { and } \mathrm{Cl} \text { - ions are present in } 1: 2 \text { ratio in a solution of aqueous calcium chloride. }

Explanation:

Here in Calcium Chloride ionic bond is present in between calcium and chlorine atoms. As we know according to Octet rule calcium have two excess atoms and for matching nearest noble gas electronic configuration. It donate two electrons to gain more stability and form \mathrm{Ca}^{2+}, while chlorine is deficient from one electron to meet nearest noble gas electronic configuration therefore two chlorine atoms accept excess electron from calcium individually and form two\mathrm{Cl}^{-} ions.

\text { Equation is as follows: } \mathrm{Ca}^{2+}+2 \mathrm{Cl}^{-} \rightarrow \mathrm{CaCl}_{2}

Hence aqueous solution of calcium chloride breaks the ionic bond pairing in one \mathrm{Ca}^{2+}and two\mathrm{Cl}^{-}ions: \mathrm{CaCl}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O} \quad \mathrm{Ca}^{2+}(\mathrm{ag})+2 \mathrm{Cl}(\mathrm{ag})

5 0
4 years ago
The percent errors of your experimental values of the specific heats may be quite large. Identify several sources of experimenta
valkas [14]

Answer:

The various sources of such errors are given below.

Explanation:

  • Sources of uncertainty or error could include necessary splattering of water leading to reduced cold water density as well as elevated temperatures of equilibration.
  • The temperature might not have been reasonably stable when developers evaluated at every phase of the investigation or research.

So that the percentage of someone specific produces heat exploratory value systems inaccuracies can be somewhat massive.

6 0
4 years ago
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