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bogdanovich [222]
3 years ago
5

A chair of mass 12.0 kg is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force F

= 40.0 N that is directed at an angle of 37.0∘ below the horizontal, and the chair slides along the floor. (a) Draw a clearly labeled free-body diagram for the chair. (b) Use your diagram and Newton’s laws to calculate the normal force that the floor exerts on the chair

Physics
1 answer:
yarga [219]3 years ago
6 0

Answer:

Explanation:

mass, m = 12 kg

Force, F = 40 N

θ = 37° below the horizontal

(a)

Diagram is attached

(b) Let N be the normal reaction

According to the diagram

N + F Sin θ = m g

N = mg - F Sin θ

N = 12 x 9.8 - 40 x Sin 37

N = 117.6 - 24.07

N = 93.53  

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The angle through which the grinding wheel rotates in the first second =  <u>5300 rad</u>

Angular velocity is, the time charge at which an object rotates, or revolves, about an axis, or at which the angular displacement between our bodies changes. within the discern, this displacement is represented via the angle θ among a line on one body and a line on the alternative.

The angular velocity is described as the charge of trade of the angular position of a rotating body. Linear speed is defined because the charge of change of displacement with respect to time whilst the item moves alongside a straight course.

Initial angular velocity of the grinding wheel = ω1 = 5500 rad/s

Final angular velocity of the grinding wheel = ω2 = 0 rad/s   (Comes to rest)

Time is taken by the grinding wheel to come to rest = T = 10 sec

Angular acceleration of the grinding wheel = α

2 = ω1 + αT

0 = 5500 + α(10)

α = - 400 rad/s2

Negative as it is deceleration.

The angle through which the grinding wheel rotates in the first second = θ

Time period = T1 = 1 sec

θ = ω₁T1 + αT1²/2

θ = (5500)(1) + (-400)(1)²/2

θ = 5300 rad

The angle through which the grinding wheel rotates in the first second =  <u>5300 rad</u>

Learn more about angular velocity here:-brainly.com/question/6860269

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