Wich sphere of the earth system includes snowfields ice caps and frozen ground
1 answer:
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The given from your problem are the following:
V = 85mph (This is miles per hour)
d = 60 feet
If you notice the units do not match. Before we can do anything else, we need to make the figures match.
In this case, we will convert 85miles per hour to feet per hour. There are 5,280 feet in 1 mile.
x 
But wait! If you think about the scenario, you are looking for how long it will take for the ball to reach the bat. The most applicable unit of time to use here is second. It would be very hard to really measure a short and instantaneous event in hours. So we convert it into feet per second:
There are 3,600 seconds in 1 hour.
x 
So now we have our new given as:
v = 124.67ft/s
d = 60 ft
The formula for time can be derived from the formula from velocity, which is:
The formula of time will then be:
All you need to do is plug in what you know and solve for what you don't know.
The answer then is 0.48s.
If you want this in hours, just divide the value in seconds by 3,600. The answer would then be 0.00013hr. (See how small it is? This is why seconds would be a more appropriate measure.)
V = 85mph (This is miles per hour)
d = 60 feet
If you notice the units do not match. Before we can do anything else, we need to make the figures match.
In this case, we will convert 85miles per hour to feet per hour. There are 5,280 feet in 1 mile.
But wait! If you think about the scenario, you are looking for how long it will take for the ball to reach the bat. The most applicable unit of time to use here is second. It would be very hard to really measure a short and instantaneous event in hours. So we convert it into feet per second:
There are 3,600 seconds in 1 hour.
So now we have our new given as:
v = 124.67ft/s
d = 60 ft
The formula for time can be derived from the formula from velocity, which is:
The formula of time will then be:
All you need to do is plug in what you know and solve for what you don't know.
The answer then is 0.48s.
If you want this in hours, just divide the value in seconds by 3,600. The answer would then be 0.00013hr. (See how small it is? This is why seconds would be a more appropriate measure.)
Answer and Explanation
• Heterotopic protons are those that when substituted by the same substituent, are structurally different. They are not similar, diastereotopic or enantiotopic.
• Diastreotopic protons refers to two protons in a molecule which, if replaced by the same substituent, would generate compounds that are diastereomers. Diastereotopic groups are often, but not always, identical groups attached to the same atom in a molecule containing at least one chiral center.
For example, the two hydrogen atoms of the C3 carbon in (S)-2-bromobutane are diastereotopic (shown in the attached image). Replacement of one hydrogen atom with a bromine atom will produce (2S,3R)-2,3-dibromobutane. Replacement of the other hydrogen atom with a bromine atom will produce the diastereomer (2S,3S)-2,3-dibromobutane.
• Homotopic protons in a compound are equivalent protons. Two protons A and B are homotopic if the molecule remains the same (including stereochemically) when the protons are interchanged with some other atom (substituent) while the remaining parts of the molecule stay fixed. Homotopic atoms are always identical, in any environment.
For example, ethane, the two H atoms on C1 and C2 carbons on the same side (as shown in the attached image) are homotopic as they exhibit the phenomenon described above.
• Enantiotopic protons are two protons in a molecule which, if one or the other were replaced (by the same substituent), would generate a chiral compound. The two possible compounds resulting from that replacement would be enantiomers.
For example, in the attached image to this answer, the two hydrogen atoms attached to the second carbon in butane are enantiotopic. Replacement of one hydrogen atom with a bromine atom will produce (R)-2-bromobutane. Replacement of the other hydrogen atom with a bromine atom will produce the enantiomer (S)-2-bromobutane.
Hope this helps!!!
