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Natali5045456 [20]
2 years ago
7

What two factors could the students change to investigate how to increase and decrease the magnetic force between the paperclip

and the magnet?
A. Students could use a heavier retort stand and thicker string.
B. Students could change the color of the rock and the paperclip they are using.
C. Students could change the position of the clamp to move the magnet father away
from the paperclip.
D. Students could move the magnet further away from the paperclip and use a more
powerful magnet instead of a bar magnet.
Physics
1 answer:
scoundrel [369]2 years ago
4 0
..............................................A
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Becomes numb. Or begins to hurt
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3 years ago
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A man is traveling on a bicycle at 14 m/s along a straight road that runs parallel to some railroad tracks. He hears the whistle
deff fn [24]

Answer:

Explanation:

b ) The problem is based on Doppler's effect of sound

f = f₀ x (V - v₀) /( V+v_s)

f is apparent frequency ,f₀ is real frequency , V is velocity of sound , v₀ is velocity of observer going away  , v_s is velocity of source going away

778  = 840 x (340 - 14)/ (340 + v_s)

340 + v_s = 341.18

v_s = 1.18 m /s

it will go  away from   the observer or the cyclist.

speed of train = 1.18 m /s

a )

For a stationary observer v₀ = 0

f = f₀ x V  /( V+v_s)

= 840 x 340 / (340 + 1.180)

= 837 Hz

6 0
2 years ago
What are the standard units of length, mass, and volume in the<br> metric system?
antoniya [11.8K]

Answer:

Meter, Gram and Liter.

Explanation:

In the metric system, the standard units for the below are;

Length  - Meter

Mass     - Gram

Volume - Liter.

8 0
3 years ago
An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper
dimulka [17.4K]

Answer:

The power output of this engine is  P =  17.5 W

The  the maximum (Carnot) efficiency is  \eta_c  = 0.7424

The  actual efficiency of this engine is  \eta _a  = 0.46

Explanation:

From the question we are told that

    The temperature of the hot reservoir is  T_h = 1250 \ K

      The temperature of the cold reservoir  is  T_c  =  322 \ K

     The energy absorbed from the hot reservoir is E_h  = 1.37 *10^{5} \ J

       The energy exhausts into  cold reservoir is  E_c  = 7.4 *10^{4} J

The power output is mathematically represented as

      P  =  \frac{W}{t}

Where t is the time taken which we will assume to be 1 hour =  3600 s  

W is the workdone which is mathematically represented as

      W =  E_h  -E_c

substituting values

       W = 63000 J

So

    P =  \frac{63000}{3600}

    P =  17.5 W

The Carnot efficiency is mathematically represented as

          \eta_c  =  1 - \frac{T_c}{T_h}

         \eta_c  =  1 - \frac{322}{1250}

         \eta_c  = 0.7424

The actual efficiency is mathematically represented as

        \eta _a  =   \frac{W}{E_h}

substituting values

         \eta _a  =  \frac{63000}{1.37*10^{5}}

         \eta _a  = 0.46

     

7 0
3 years ago
A rifle fires a 2.90 x 10-2-kg pellet straight upward, because the pellet rests on a compressed spring that is released when the
iren2701 [21]

Answer: 586.60N/m

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In this scenario, the elastic potential energy of the spring is converted into potential energy.

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=(2*2.90*10^-2*9.8*7.23)/(8.37*10^-2)^2

=586.599

Therefore K = 586.60N/m

7 0
3 years ago
Read 2 more answers
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