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Black_prince [1.1K]
2 years ago
15

A plate of an alloy steel has a plane-strain fracture toughness of 50 MPa-m1/2. If it is known that the largest surface crack is

0.5 mm long, and that the value of Y is 1.1, which of the following can be said about this plate when a tensile stress of 1200 MPa is applied?
a. It is not possible to determine whether or not the plate will fracture.
b. The plate will definitely not fracture.
c. The plate will definitely fracture.
Chemistry
1 answer:
Angelina_Jolie [31]2 years ago
8 0

Answer:

Option C (The plate will definitely fracture) is the correct option.

Explanation:

According to the question,

The critical stress will be:

⇒ \sigma_c = \frac{K}{Y \sqrt{\pi a} }

By putting the values, we get

        =\frac{50}{1.1\times \sqrt{\pi\times 0.5} }

        =1146.87 \ MPa

So,

  • \sigma_c < \sigma_{apply}
  • 1146.87

Thus, the above is the correct response.

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ZanzabumX [31]
C
Explanation- equals 459
3 0
2 years ago
. Sulfur dioxide can be produced in the laboratory by the reaction of hydrochloric acid and a sulfite salt such as sodium sulfit
shutvik [7]

Answer:

Mass of SO₂ can be made from 25.0 g of Na₂SO₃ and 22 g of HCl = 12.672 g

Explanation:

SO₂( sulfur dioxide) can be produced in the lab. by the reaction of hydrochloric acid & sulphite salt such as sodium.

        the balanced chemical equation is as follows

                       Na₂SO₃ + 2 HCl → 2 NaCl + SO₂ + H₂O

Moles of Na₂SO₃ = \frac{Mass}{Molecular mass} =\frac{25}{126} = 0.198

Moles of HCl = \frac{mass}{molecular mass}=\frac{22}{36.5}= 0.6

using mole ratio method to find limiting reagent

      For sodium sulfite \frac{mole}{stoichiometry}  = \frac{0.198}{1}= 0.198

 for HCl \frac{mole}{stoichiometry}  = \frac{0.6}{2}= 0.3

since <u>sodium sulfite</u> is <u>limiting reactant</u> for above chemical reaction

1 mole of Na₂SO₃ produce 1 mole of SO₂

0.198 mole of Na₂SO₃ produce 0.198 mole of SO₂

∴ Mass of SO₂ produce = mole x molar mass of SO₂

                                       = 0.198 x 64

                                       = 12.672 g

8 0
3 years ago
What may be expected when K &lt; 1.0?
Romashka [77]
The reaction will generally form more reactants than products.
8 0
3 years ago
Read 2 more answers
3. A student measured 15.0 grams of ice in a beaker. The beaker was then
gregori [183]

Answer:

The heat that was used to melt the 15.0 grams of ice at 0°C is 4,950 Joules

Explanation:

The mass of ice in the beaker = 15.0 grams

The initial temperature of the ice = 0°C

The final temperature of the ice = 0°C

The latent heat of fusion of ice = 330 J/g

The heat required to melt a given mass of ice = The mass of the ice to be melted × The latent heat of fusion of ice

Therefore, the heat, Q, required to melt 15.0 g of ice = 15.0 g × 330 J/g = 4,950 J

The heat that was used to melt the 15.0 grams of ice = 4,950 Joules.

3 0
3 years ago
The force of 20 N acts upon a 5kg block. What is the acceleration of the block?
charle [14.2K]

Answer:

<h2>The answer is 4 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

where

a is the acceleration

f is the force

m is the mass

From the question

f = 20 N

m = 5 kg

We have

a =  \frac{20}{5}  \\

We have the final answer as

<h3>4 m/s²</h3>

Hope this helps you

8 0
3 years ago
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