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Black_prince [1.1K]
2 years ago
15

A plate of an alloy steel has a plane-strain fracture toughness of 50 MPa-m1/2. If it is known that the largest surface crack is

0.5 mm long, and that the value of Y is 1.1, which of the following can be said about this plate when a tensile stress of 1200 MPa is applied?
a. It is not possible to determine whether or not the plate will fracture.
b. The plate will definitely not fracture.
c. The plate will definitely fracture.
Chemistry
1 answer:
Angelina_Jolie [31]2 years ago
8 0

Answer:

Option C (The plate will definitely fracture) is the correct option.

Explanation:

According to the question,

The critical stress will be:

⇒ \sigma_c = \frac{K}{Y \sqrt{\pi a} }

By putting the values, we get

        =\frac{50}{1.1\times \sqrt{\pi\times 0.5} }

        =1146.87 \ MPa

So,

  • \sigma_c < \sigma_{apply}
  • 1146.87

Thus, the above is the correct response.

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the percent yield of the reaction is 100%.

The percent yield is calculated as the experimental yield divided by the theoretical yield x 100%:

% yield = actual yield / theoretical yield * 100%

% yield of a reaction in this case Rate

In this case, the molar mass of NaBr is 102.9 g / mol, as you know:

444 actual yield = 7.08 mol x 102.9 g / mol = 728.532 g

theoretical yield = 7.08 mol x 102.9 g / mol = 728.532 g

, Replaced by the definition of percent yield:

percent yield = 728.532 grams / 728.532 grams * 100%

percent yield = 100%

Finally, the percent yield of the reaction is 100%.

<h3 />

FeBr3 is iron bromide. Also known as iron bromide. Iron bromide is an ionic compound in which iron is in a +3 oxidation state.

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5 0
2 years ago
The pressure in a car tire is 198 kPa at 27°C. After a long drive, the pressure
AlekseyPX

Answer : The temperature of the air in the tire is, 341 K

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

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P_2 = final pressure = 225 kPa

T_1 = initial temperature = 27^oC=273+27=300K

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Now put all the given values in the above equation, we get:

\frac{198kPa}{300K}=\frac{225kPa}{T_2}

T_2=340.9K\approx 341K

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