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Xelga [282]
3 years ago
11

Is it true or false that some ecosystems can recover after a disturbance

Chemistry
2 answers:
Contact [7]3 years ago
7 0

Answer: i think  no but what kind of distubance

Explanation:

Sergio039 [100]3 years ago
3 0

Answer is True. They can in one lifetime by either humans or natural

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What reaction involves one element replacing an element in a compound that is from the same activity series?
Marina86 [1]

Answer: Displacement reaction

Explanation: Displacement reaction is a reaction in which elements higher in the activity series displaces those lower in the activity series in a compound. For example, the reaction between zinc and hydrochloric acid.

Zn + 2HCl —> ZnCl2 + H2

Zn displaces H2 from acid because Zn is higher than hydrogen in the activity series.

3 0
4 years ago
A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.6
Juli2301 [7.4K]

Answer:

\% m=40.46\%

Explanation:

Hello there!

in this case, according to the given information, it turns out firstly necessary for us to write up the chemical equation as shown below:

BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl

Thus, we calculate the mass of BaCl2 stoichiometrically related to the produced 1.658 g of precipitate in order to discard it from the sample:

m_{BaCl_2}=1.658gBaSO_4*\frac{1molBaSO_4}{233.38 gBaSO_4} *\frac{1molBaCl_2}{1molBaSO_4}*\frac{208.23 gBaCl_2}{1molBaCl_2}\\\\m_{BaCl_2}=1.479gBaCl_2

Thus, the mass percentage is calculated as shown below:

\% m=\frac{1.479g}{3.656g}*100 \% \\\\\% m=40.46\%

Regards!

5 0
3 years ago
A student prepares a 100.0 mL solution using 44.7 grams of potassium nitrite. They then take 11.9 mL of this solution and dilute
Naddik [55]

Answer:

0.52 g of KNO₃ are contained in 19.7 mL of diluted solution.

Explanation:

We can work on this problem in Molarity cause it is more easy.

Molarity (mol/L) → moles of solute in 1L of solution.

100 mL of solution = 0.1 L

We determine moles of solute: 44.7 g . 1mol /101.1 g = 0.442 mol of KNO₃

Our main solution is 0.442 mol /0.1L = 4.42 M

We dilute: 4.42 M . (11.9mL / 200mL) = 0.263 M

That's concentration for the diluted solution.

M can be also read as mmol/mmL, so let's find out the mmoles

0.263 M . 19.7mL = 5.18 mmol

We convert the mmol to mg → 5.18 mmol . 101.1 mg / mmol = 523.7 mg

Let's convert mg to g → 523.7 mg . 1 g / 1000 mg = 0.52 g

6 0
3 years ago
Calculate the pH of a solution that is 0.205M benzoic acid and 0.230M sodium benzoate, a salt whose anion is the conjugate base
pickupchik [31]

Answer:

pH = 4.25

Explanation:

A solution composed of a weak acid and its conjugate base is a <em>buffer solution</em>. To calculate the pH of a buffer solution we use the Henderson-Hasselbach equation:

pH = pKa + log ([conjugate base]/[weak acid]

In this case, we have the following data:

[conjugate base] = [sodium benzoate] = 0.230 M

[weak acid] = [benzoic acid] = 0.205 M

The pKa of benzoic acid is 4.2. So, we introduce the data in the equation:

pH = 4.2 + log (0.230 M/0.205 M) = 4.2 + 0.050 = 4.25

4 0
3 years ago
What is the chemical formula of diphosphorus monoxide?
Daniel [21]

Answer:

The chemical formula of diphosphorus monoxide is OP2.

I'm not sure if this is correct, but hope it helps! :)

7 0
3 years ago
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