Answer:
Exercise 1
a) 140 m
b) 100 m
c) 180 m
d) 140 m
Exercise 2
a) 20 yards
b) 30 yards
c) 20 yards
d) 55 yards
Exercise 3
a) 11 Kilometers
b) 7 Kilometers
Explanation:
Exercise 1
Distance from B to C = 140 m
Distance from to D = 100 m
Total distance = 100+40+40 = 180 m
Total displacement i.e. distance between A and D is 140 m
Exercise 2
a) Distance from B to C = 35 -15 = 20 yards
b) Distance from C to D = 5 + 35 = 30 yards
c) Distance from B to D = 5 + 15 = 20 yards
d) Displacement = 5 + 50 = 55 yards
Exercise 3
a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers
b) Displacement = 5-2 + 4 = 7 Kilometers
Answer:
4s2
Explanation:
The electronic configuration of zinc in the ground state of the atom is 1s22s22p6 3s23p63d104s2. It can be written in a condensed form by showing the inert gas core as follows; [Ar] 3d¹⁰ 4s².
Zinc has a pseudo inert gas configuration when the 4s electrons are removed during oxidation. Hence this sublevel is usually affected when zinc atoms are oxidized according to the scheme;
Zn---->Zn^2+ + 2e-
It is given that the charge on potassium is +1 i.e. Potassium is a cation, K⁺
The charge on selenium is given as -2, i.e. selenium is an anion, Se²⁻
The two ions are shown to combine to form a molecule: KXSeY where X and Y correspond to the proportions in which the two atoms combine.
Since the molecule is neutral, the positive and negative charges need to be balanced. This is possible only if 2 units of K⁺ combines with 1 unit of Se²⁻.
Therefore, the formula would be K₂Se
X = 2 and Y = 1
Answer:
The answer to your question is V₁ = 12.5 ml
Explanation:
Data
Volume = V₁?
[NaOH] = C₁ = 4.0 M
Volume 2 = V₂ = 100 ml
[NaOH] = C₂ = 0.5 M
Formula of dilution
V₁C₁ = V₂C₂
Solve for V₁ (original solution)
V₁ = 
Substitution
V₁ = 
Simplification
V₁ = 
Result
V₁ = 12.5 ml
Crust, Mantle, Outer core, Inner Core