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Anvisha [2.4K]
3 years ago
9

Marcie solved the following inequality, and her work is shown below:

Mathematics
2 answers:
Finger [1]3 years ago
4 0

Answer:

The Answer is C. When dividing by −8, she did not change the ≤ to ≥.


faust18 [17]3 years ago
3 0
-2(x-5)-12≤4+6(x+3)
Use distributive property
-2(x)-2(-5)-12≤4+6(x)+6(3)
-2x+10-12≤4+6x+18
-2x-2≤6x+22
Add 2x to both side
-2x-2+2x≤6x+22+2x
-2≤8x+22
Subtract 22 to both side
-2-22≤8x+22-2
-24≤8x
Divided 8 to both side
-24/8≤8x/8
-3≤x
or
x≥-3
Um, there is another way to prove that there is one mistakes
-2(x-5)-12≤4+6(x+3)
-2x+10-12≤4+6x+18
-2x-2≤6x+22
-8x-2≤22
-8x≤24
x≥-3, so her mistakes is:
C. When dividing by −8, she did not change the ≤ to ≥. As a result, C is the final answer. Hope it help!
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J is the midpoint of HK¯¯¯¯¯¯¯ . What are HJ, JK, and HK?
lana [24]
Since J is the midpoint of HK, that means HK is split into two sections HJ and JK that are the same length.

1) You are told that the m<span>easure of segment HJ = 9x-2 and that of segment JK = 4x+13. Since you also know they are equal lengths, you can set these equations equal to each other to find the value of x!
HJ = JK
</span>9x-2 = 4x+13
5x = 15
x = 3

2) Now you know x = 3. Plug that into your given equations for HJ and JK to find the length of each segment (or a shortcut would be to find one of them, and then you also know the other is the same length. I'm doing both, just to make sure I don't make a silly mistake!):
HJ = <span>9x-2 
</span>HJ = 9(3) - 2
HJ = 27 - 2
HJ = 25

JK = 4x + 13
JK = 4(3) + 13
JK = 12 + 13
JK = 25

3) Finally, the length of HK is just the length of HJ + JK, or HK = 25 + 25 = 50.

-----

Answer: HJ = 25, JK = 25, HK = 50
4 0
3 years ago
The equation v/2 -21=-15 is solved in several steps below.
Arada [10]

Answer:

V/2 - 21 = -15

V/2 - 21 + 21 = -15 + 21

V/2 + 0 = 6

V/2 * 2 = 6 * 2

V = 12

8 0
4 years ago
Mr. Paz wants to put a fence around a baseball field. Which tool and unit should he use to measure the perimeter of the baseball
Leto [7]
A meter stick of something large like that
6 0
3 years ago
Read 2 more answers
PLEASE HELP ME!! no spame
mina [271]
1/8
I’m adding random stuff to send the answer!:)
3 0
3 years ago
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I need help breaking this down
sergeinik [125]

Answer:

see explanation

Step-by-step explanation:

Given

2cosΘ - \sqrt{2} = 0 ( add \sqrt{2} to both sides )

2cosΘ = \sqrt{2} ( divide both sides by 2 )

cosΘ = \frac{\sqrt{2} }{2}

Since cosΘ > 0 then Θ is in first and fourth quadrants, hence

Θ = cos^{-1} ( \frac{\sqrt{2} }{2} ) = \frac{\pi }{4}

OR

Θ = 2π - \frac{\pi }{4} = \frac{7\pi }{4}

solutions are Θ = \frac{\pi }{4}, \frac{7\pi }{4}

3 0
3 years ago
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