B) (-4, -4)

When moving to the right you are moving to a more POSITIVE region on the x-axis; meaning, the y-value (vertical axis) does not get affected unless you’re moving up or down.

Remember: (-6, -4)
X = -6
Y = -4

If you move 2 units to the right (x-axis) you go from -6 + 2 which equals -4. And again, you’re not moving up and down so your
y-value stays the same and your new coordinates are (-4, -4)

7 0

3 years ago

PLEASE HELP MEE I CAN'T SOLVE THIS BY MYSELF!

UNO [17]

Answer:

x = 22

Step-by-step explanation:

The figure is attached below.

Its given that SV is parallel to RU. We have to find the value of x.

Observe that, if we join point V to U, we will obtain a parallelogram RSVU. One of the properties of a parallelogram is that the sum of its two adjacent angles is always 180 degrees.

So, the two adjacent angles would be: ∠S and ∠R

From the figure:

∠S = 5x + 4

∠R = 44 + x

Since,

∠S + ∠R must be 180 degrees, we can write:

∠S + ∠R = 180

5x + 4 + 44 + x = 180

6x + 48 = 180

6x = 132

x = 22

Therefore, the value of x is 22.

6 0

3 years ago

The distance from place A to place B is 100 yards. What is this distance in terms of feet?

Rashid [163]

Answer:

Step-by-step explanation:

one yard is 3 feet

100x3=300

6 0

3 years ago

Read 2 more answers

Joe can cut and split a cord of firewood in 3 fewer hours than Dwight can. When they work together, it takes them 2 hours. How

aalyn [17]

Answer:

Dwight will take 6 hours to finish the job alone and Joe will take 3 hours to finish the job alone.

Step-by-step explanation:

Let us assume the time taken by Dwight to split a cord of firewood = K hrs

So, the per hour rate of Dwight = $(\frac{1}{K})$

As, Joe uses 3 LESS hours then Dwight.

So, the time taken by Joe to split a cord of firewood = (K- 3) hrs

So, the per hour rate of Joe = $(\frac{1}{K-3})$

Now, when both of them wok together, it takes them 2 hours.

So, the per hour rate of BOTH of them = $(\frac{1}{2})$

⇒ Per hour rate of ( Dwight + Joe) = $(\frac{1}{2} )$

$\implies (\frac{1}{K}) + (\frac{1}{K-3}) = (\frac{1}{2})$

Now, solving for the value of K , we get:

$(\frac{1}{K}) + (\frac{1}{K-3}) = (\frac{1}{2})\\\implies \frac{(K-3) + K}{K (K-3)} = (\frac{1}{2})\\\implies 2(2K -3) = K^2 - 3K\\\implies k^2 - 3K -4K +6 = 0\\\implies K^2 - 7K + 6= 0\\\implies K^2 - 6K - K + 6= 0\\\implies K(K-6) -1(K - 6)= 0\\\implies (K-6)(K-1) = 0$

Implies either K = 6 Or K = 1

But if K = 1, (K-3) = 1- 3 = -2 hours would be A CONTRADICTION.

⇒ K = 6 hours

Hence, Dwight will take 6 hours to finish the job alone and Joe will take (k-3) = (6-3) = 3 hours to finish the job alone.

8 0

3 years ago