Solving for 'y'
2x - 2y + 5 = 0
Add 2y on both sides
2x + 5 = 2y
Divide by 2 on both sides
y = x + 5/2
y = x + 2.5
Solving for 'x'
2x - 2y + 5 = 0
Subtract 2x on both sides.
-2y + 5 = -2x
Divide 2x on both sides
x = y - 5/2
x = y - 2.5
Answer:
See below.
Step-by-step explanation:
Using the Rational Roots Theorem:
Factors of 3: 1, 3 ( = p).
Factors of 6: 1,2,3,6 ( = q).
Possible real roots are a 1 or 3 from p / q = +/- 1/1, +/- 3/1 , +/-1/2, +/- 1/3 , +/- 1/6, +/- 3/2.
Answer:D
Step-by-step explanation:y-4=3(x-1)
y-4=0 3(x-1)
y=-4 , 3x-3
y=-4=3x-3
3 3
y=-4, = x=1
y-x=1+4=5
3/(x-1) - 1/(x^2-1) = 5/(x-1)
Subtract 3/(x-1) from both sides
-1/(x^2-1) = 2/(x-1)
Factor x^2 - 1
-1/[(x-1)(x+1] = 2/(x-1)
Multiply by (x-1)(x+1) on both sides
-1 = 2 (x+1)
-1 = 2x + 2
Subtract 2 from both sides
-3 = 2x
Divide by 2 on both sides
-3/2 = x
