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Sonbull [250]
3 years ago
6

Beer's Law states that A=ebc, where A is the absorbance, ε is the molar absorptivity of the solute, b is the path length, and c

is the concentration. Identify the experimental evidence from the activity that you have for the dependence of absorbance on each variable
The evidence for the dependence of absorbance on the variable ε is:_________

a. increasing the cuvette width increases the absorbance.
b. changing the compound changes the absorbance behavior.
c. adding more water decreases the absorbance.
Chemistry
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

b. changing the compound changes the absorbance behavior.

Explanation:

  • Option a) would be akin to modifying the <em>path length</em>, b.
  • Option b) would involve using a different solute, as such, there would be another <em>molar absortivity</em>, ε.
  • Option c) would decrease the<em> concentration</em> (c) of the solute, which would explain why the absorbance would decrease as well.
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The question is incomplete, here is the complete question:

At 25°C Henry's Law constant for carbon dioxide gas in water is 0.031 M/atm . Calculate the mass in grams of gas that can be dissolved in 425. mL of water at 25°C and at a partial pressure of 2.92 atm. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of carbon dioxide that can be dissolved is 1.7 grams

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{CO_2}

where,

K_H = Henry's constant = 0.031M/atm

C_{CO_2} = molar solubility of carbon dioxide gas

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Putting values in above equation, we get:

C_{CO_2}=0.031M/atm\times 2.92 atm\\\\C_{CO_2}=0.0905M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of carbon dioxide = ? g

Molar mass of carbon dioxide = 44 g/mol

Molarity of solution = 0.0905mol/L

Volume of solution = 425 mL

Putting values in above equation, we get:

0.0905mol/L=\frac{\text{Mass of carbon dioxide}\times 1000}{44g/mol\times 425}\\\\\text{Mass of solute}=\frac{44\times 425\times 0.0905}{1000}=1.7g

Hence, the mass of carbon dioxide that can be dissolved is 1.7 grams

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