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yaroslaw [1]
3 years ago
14

Examine the circuit. Pretend you are an electron flowing through this circuit and you are with a group of other electrons. Sudde

nly you come to the ‘fork in the road’ and you and some of the other electrons are temporarily separated. A short while later you are back together with the other electrons. This type of circuit is called a(n) ____________ circuit.
PLEASE HELP!!!
Physics
2 answers:
melamori03 [73]3 years ago
7 0

You knew that this question is ridiculously easy.  So, just to
make it harder, you decided not to let us see the picture, so
that we could not "examine the circuit".

The description is talking about a parallel circuit.  The other
kind is a series circuit, and that one has no forks in the road.
valentinak56 [21]3 years ago
5 0

Answer:

parallel

Explanation:

In an electric circuit a ‘fork in the road’ appears in a parallel configuration. This kind of circuit is characterized by the different currents each 'road' take after the bifurcation, depending on the different resistance each one has. The voltage remains the same for every 'road'.

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What type of charge will an object have if the object contains less protons than electrons?
Burka [1]

Answer:

Hello, I believe it would have a negative charge considering protons have a positive charge while elctrons have a negative charge

Explanation:

6 0
3 years ago
The reflective surface of a CD consists of spirals of equally spaced grooves. If you shine a laser pointer on a CD, each groove
Ipatiy [6.2K]

Answer:

d = 1.55 * 10⁻⁶ m

Explanation:

To calculate the distance between the adjacent grooves of the CD, use the formula, d = \frac{m \lambda}{sin(A_{m}) }..........(1)

The fringe number, m = 1 since it is a first order maximum

The wavelength of the green laser pointer, \lambda = 532 nm = 532 * 10⁻⁹ m

Distance between the central maximum and the first order maximum = 1.1 m

Distance between the screen and the CD = 3 m

A_{m} = Angle between the incident light and the diffracted light

From the setup shown in the attachment, it is a right angled triangle in which

sin(A_{m}) = \frac{opposite}{Hypotenuse} \\sin(A_{m}) =\frac{1.1}{\sqrt{1.1^{2}+3^{2}}}

sin(A_{m} ) = 0.344\\A_{m} = sin^{-1} 0.344\\A_{m} = 20.14^{0}

Putting all appropriate values into equation (1)

d = \frac{1* 532*10^{-9} }{0.344 }\\d = 0.00000155 m\\d = 1.55 * 10^{-6} m

3 0
3 years ago
A car with a total mass of 1800 kg (including passengers) is driving down a washboard road with bumps spaced 4.9 m apart. The ri
Drupady [299]

Answer:

k = 9.6 x 10^5 N/m or 9.6 kN/m

Explanation:

First, we need to use the expression to calculate the spring constant which is:

w² = k/m

Solving for k:

k = w²*m

To get the angular velocity:

w = 2πf

The problem is giving the linear velocity of the car which is 5.7 m/s. With this we can calculate the frequency of the car:

f = V/x

f = 5.7 / 4.9 = 1.16 Hz

Now the angular velocity:

w = 2π*1.16

w = 7.29 rad/s

Finally, solving for k:

k = (7.29)² * 1800

k = 95,659.38 N/m

In two significant figures it'll ve 9.6 kN/m

5 0
3 years ago
Read 2 more answers
two forces 3N and 4N act on a body in a direction due north and due East respectively calculate their equivalent​
Lostsunrise [7]

Two forces 3N and 4N act on a body in a direction due north From East, the equilibrant's angle is given by \theta=\tan ^{-1} \frac{3}{4}=36.8^{\circ}.

<h3>What are equilibrium and resultant force?</h3>

The equilibrium force is the balanced force when the net force acting is zero and is the exact opposite of the consequent force. The resultant force is one single force replaced by numerous forces.

<h3>Briefing:</h3>

3N and 4N are the two forces pulling on a body.

The forces work along the North and the East, which are perpendicular to one another.

The resultant of the forces, which is provided by the equilibrant force,

R  = √(3)²+(4)²

R = 5N

From East, the equilibrant's angle is given by

\theta=\tan ^{-1} \frac{3}{4}=36.8^{\circ}

To know more about equilibrium force visit:

brainly.com/question/12582625

#SPJ9

6 0
1 year ago
I need help ASAPP
Tresset [83]

Answer: For the first part the answer is Radio Waves and the second part’s answer is gamma ray.

6 0
3 years ago
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