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yaroslaw [1]
3 years ago
14

Examine the circuit. Pretend you are an electron flowing through this circuit and you are with a group of other electrons. Sudde

nly you come to the ‘fork in the road’ and you and some of the other electrons are temporarily separated. A short while later you are back together with the other electrons. This type of circuit is called a(n) ____________ circuit.
PLEASE HELP!!!
Physics
2 answers:
melamori03 [73]3 years ago
7 0

You knew that this question is ridiculously easy.  So, just to
make it harder, you decided not to let us see the picture, so
that we could not "examine the circuit".

The description is talking about a parallel circuit.  The other
kind is a series circuit, and that one has no forks in the road.
valentinak56 [21]3 years ago
5 0

Answer:

parallel

Explanation:

In an electric circuit a ‘fork in the road’ appears in a parallel configuration. This kind of circuit is characterized by the different currents each 'road' take after the bifurcation, depending on the different resistance each one has. The voltage remains the same for every 'road'.

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A mechanic jacks up the front of a car to an angle of 8.0° with the horizontal in order to change the front tires. the car is 3.
Zina [86]
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5 0
4 years ago
Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons p
boyakko [2]

Answer:

The number of free electrons per cubic meter is 7.61\times 10^{28}\ m^{-3}

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal, \sigma=6.8\times 10^7\ \Omega^{-1}m^{-1}

Density of metal, \rho=10.5\ g/cm^3

Atomic weight, A = 107.87 g/mol

Let n is the number of  free electrons per cubic meter such that,

n=1.3\ N

n=1.3(\dfrac{\rho N_A}{A})

Where

\rho is the density of silver atom

N_A is the Avogadro number

A is the atomic weight of silver

n=1.3\times (\dfrac{10.5\ g/cm^3\times 6.02\times 10^{23}\ atoms/mol}{107.87\ g/mol})

n=7.61\times 10^{22}\ cm^{-3}

or

n=7.61\times 10^{28}\ m^{-3}

Hence, this is the required solution.

6 0
3 years ago
1.20 Newton force is working on a 250 gram object. What is the acceleration?
Leokris [45]

Answer:

The answer is B

Explanation:

250g = 0.25kg

F = m × a

a = F/m

= 1.2/0.25

= 4.8m/s²

7 0
3 years ago
A major league pitcher can throw a baseball with a kinetic energy of 150 J. How much work must the pitcher do to the ball to giv
kenny6666 [7]

Answer:

A= 150 J

Explanation:

Kinetic energy is the energy of an object in motion.

The formula for kinetic energy is ;

K.E = 1/2 * m *v²  where m is mass and v is velocity

Work done is equal to change in kinetic energy

W= Δ K.E

Given that K.E = 150 J

Taking that the ball was stationary before it was thrown, this makes its initial kinetic energy to be 0 J so the work done will be

W=  Δ K.E

W= 150 - 0

W= 150 J

4 0
3 years ago
Avogadro’s law and charles’s law describe a proportionality of the volume of a gas when the pressure is constant. Describe the p
yaroslaw [1]

Answer:PV/T

Explanation:Here, PV / T = k shows how pressure, volume and temperature relate to each other, where k is a constant number.

The formula for the combined gas law can be adjusted to compare two sets of conditions in one substance. P1V1 / T1 = P2V2 / T2

4 0
4 years ago
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