He goes 12km north 6km east 12km south 3km west what is the distance and displacement
1 answer:
Distance is 33 km, displacement is 3 km east
Explanation:
- Distance is a scalar quantity equal to the total length of the path covered by an object during its motion, regardless of its direction.
- Displacement is a vector connecting the starting position of motion of an object to its final position. It is a vector quantity, therefore it has both magnitude and direction.
In this problem, the motion of the person is:
12 km north
6 km east
12 km south
3 km west
Therefore, the distance is:
The displacement instead can be calculated by comparing the final position with the initial position. We notice that:
- the person goes 12 km north and 12 km south, so he didn't move in the north-direction
- The person goes 6 km east and 3 km west, so his final position is 3 km east
Therefore, the displacement is 3 km east.
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Answer: The area of brick in contact with the floor is 1539 .
Explanation:
Given: Length = 19 cm
Width = 9 cm
Height = 9 cm
As the brick is rectangular in shape. Hence, its area will be calculated as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that area of brick in contact with the floor is 1539 .
Answer:
The speed does it head toward the goal = 41.87
Explanation:
Mass = 0.107 kg
Initial velocity ( u ) = 0
Force (F) = 28 N
Time = 0.16 sec
From newton's second law, Force = mass × acceleration
⇒ F = m × a
⇒ 28 = 0.107 × a
⇒ a = 261.7 --------- (1)
This is the value of acceleration.
Final speed of the mass is calculated by the equation V = U + at
⇒ U = 0 because mass in in rest position at start.
⇒ V = a t
Put the values of acceleration and time in above formula we get
⇒ V = 261.7 × 0.16
⇒ V = 41.87
Therefore the speed does it head toward the goal = 41.87