Explanation:
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He goes 12km north 6km east 12km south 3km west what is the distance and displacement
1 answer:
Distance is 33 km, displacement is 3 km east
Explanation:
- Distance is a scalar quantity equal to the total length of the path covered by an object during its motion, regardless of its direction.
- Displacement is a vector connecting the starting position of motion of an object to its final position. It is a vector quantity, therefore it has both magnitude and direction.
In this problem, the motion of the person is:
12 km north
6 km east
12 km south
3 km west
Therefore, the distance is:
The displacement instead can be calculated by comparing the final position with the initial position. We notice that:
- the person goes 12 km north and 12 km south, so he didn't move in the north-direction
- The person goes 6 km east and 3 km west, so his final position is 3 km east
Therefore, the displacement is 3 km east.
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Ir=Initial Intensity/Area of spread=Io4πr2
Ir∝1r2
It is seen from this expression that intensity is inversely proportional to the square of the distance. As we move away from the light source the intensity decreases at the rate of square of the distance from the source.
Brightness being the perception of intensity. more the intensity more bright the object is perceived and vice versa.
Ir∝1r2
It is seen from this expression that intensity is inversely proportional to the square of the distance. As we move away from the light source the intensity decreases at the rate of square of the distance from the source.
Brightness being the perception of intensity. more the intensity more bright the object is perceived and vice versa.
Answer:
a) F = 2.25 10³ N, b) REPULSIVE.
Explanation:
a) The electric force is given by coulomb's law
F = k q1q2 / r2
in this case nso indicate that the two charges have the same value
q₁ = q₂ = 2.5 10⁻⁶ C
Let's reduce the magnitudes to the SI system
r = 0.5 cm (1m / 100cm) = 5 10⁻³ m
let's calculate
F =
F = 2.25 10³ N
b) In electricity, electric charges of the same sign repel and those of the opposite sign attract
In this exercise, the balls are equal and are rubbed with the same material, for which it acquires charges of the same type, consequently, as the charges are of the same type, they indicate that the negative force is REPULSIVE.