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harina [27]
3 years ago
10

Complete the equation for the standard form of the line that has an x-intercept of -5 and a y-intercept of -4.

Mathematics
1 answer:
Verdich [7]3 years ago
7 0

Answer:

Intercept form     \frac{x}{-5} + \frac{y}{-4} = 1

The standard form of the equation of the line

   4 x + 5 y +20 =0

Step-by-step explanation:

<u><em>Explanation</em></u>

Given that x-intercept (a) = -5

and y-intercept (b) = -4

Intercept form

                 \frac{x}{a} + \frac{y}{b} = 1

                \frac{x}{-5} + \frac{y}{-4} = 1

          ⇒   \frac{4x+5y}{-20}  = 1

                4 x + 5 y = -20

<u><em>Final answer:-</em></u>

The standard form of the equation of the line

               4 x + 5 y +20 =0

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Low Temperatures This Week (Degrees Fahrenheit) 4 10 6 9 6 Low Temperatures Last Week (Degrees Fahrenheit) 13 9 5 8 5 Which measures of center or variability are greater than 5 degrees? Select three choices.

a) the mean of this week’s temperatures

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a) the mean of this week’s temperatures

b) the mean of last week’s temperatures

c) the range of this week’s temperatures

Step-by-step explanation:

I would be verifying the options a, b, and c in my answer above through calculations which are shown below.

We were given the following data:

Low Temperatures This Week (Degrees Fahrenheit)

4, 10, 6, 9, 6

Low Temperatures Last Week (Degrees Fahrenheit)

13, 9, 5, 8, 5

We are to find which measures of center or variability are greater than 5 degrees.

Option a

The mean of this week’s temperatures

(4+ 10+ 6+9+ 6) °F ÷ 5 = 35 °F ÷5 = 7°F

Option a is correct because it measures of center or variability which is 7 °F is higher than 5°F

Option b

The mean of last week’s temperatures

(13+ 9 + 5 + 8 + 5) °F = 40°F ÷ 5 = 8°F

Option b is correct , because its measure of variability which is 8°F is greater than 5°F.

Option c

the range of this week’s temperatures

This week's temperature is given as

(4, 10, 6, 9, 6) °F

Range is defined as the difference between the highest number and the lowest number

Range of this week's temperature = (10 - 4) °F = 6°F

Hence Option c is correct because it measures of center or variability which is 6°F is greater than 5°F

From the above calculations we can accurately confirm that options a, b, and c are correct because the measures of their center or variability is greater than 5°F

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