3 years ago

Question 1 of 25

Chemistry

1 answer:

Vanyuwa [196]3 years ago

7 0

Answer:

C. Dalton

Explanation:

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Which ion will most likely form a precipitate when reacted with SO42 ?

Charra [1.4K]

<h2>Answer:Ba $^2+$ </h2>

Explanation:

option A:

$SO_{4}^{2-}$ is an anion and $Cl^{1-}$ is also an anion.So,there is no reaction.

option B:

$K^{+}$ reacts with $SO_{4}^{2-}$ to form $K_{2}SO_{4}$ .

Since $K$ is a first group element,all its salts are soluble in water.

Hence no precipitate is formed.

option C:

$Na^{+}$ reacts with $SO_{4}^{2-}$ to form $Na_{2}SO_{4}$ .

Since $Na$ is a first group element,all its salts are soluble in water.

Hence no precipitate is formed.

option D:

$Ba^{2+}$ reacts with $SO_{4}^{2-}$ to form $BaSO_{4}$ .

Solubility of sulphates of second group elements decrease down the group.

So, $BaSO_{4}$ is a precipitate.

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3 years ago