1: Mercury - Hg
2: Silver - Ag
3: Gold - Au
4. Aluminium - Al
5: Iron - Fe
6: Helium - He
7: Calcium - Ca
8: Magnesium - Mg
9: Nickel - No
The pounds of alum produced when 0.26 g of hydrogen was produced are 0.0434 lb.
First, let's convert 0.126 g of hydrogen to moles using its molar mass (2.02 g/mol).
![0.126 g \times \frac{1moo}{2.02 g} = 0.0624 mol](https://tex.z-dn.net/?f=0.126%20g%20%5Ctimes%20%5Cfrac%7B1moo%7D%7B2.02%20g%7D%20%3D%200.0624%20mol)
Let's consider the steps to make alum (KAl(SO₄)₂⋅12H₂O) from aluminum (Al).
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2 Al(s) + 2 KOH(aq) + 6 H₂O(l) →2 KAl(OH)₄(aq) + 3 H₂(g)
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2 KAl(OH)₄(aq) + H₂SO₄(aq) → 2 Al(OH)₃(s) + K₂SO₄(aq) + 2 H₂O(l)
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2 Al(OH)₃(s) + H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 6 H₂O(l)
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K₂SO₄(aq) + Al₂(SO₄)₃(aq) + 24 H₂O(l) → 2 KAl(SO₄)₂⋅12H₂O(s)
To relate H₂ to KAl(SO₄)₂⋅12H₂O, we need to consider the appropriate molar ratios:
- In step 1, the molar ratio of H₂ to KAl(OH)₄ is 3:2.
- In step 2, the molar ratio of KAl(OH)₄ to Al(OH)₃ is 2:2.
- In step 3, the molar ratio of Al(OH)₃ to Al₂(SO₄)₃ is 2:1.
- In step 4, the molar ratio of Al₂(SO₄)₃ to KAl(SO₄)₂⋅12H₂O is 1:2.
The moles of KAl(SO₄)₂⋅12H₂O produced from 0.0624 moles of H₂ are:
![0.0624 molH_2 \times \frac{2molKAl(OH)_4}{3molH_2} \times \frac{2molAl(OH)_3}{2molKAl(OH)_4} \times \frac{1molAl_2(SO_4)_3} {2molAl(OH)_3} \times \frac{2molAlum}{1molAl_2(SO_4)_3} =0.0416 mol Alum](https://tex.z-dn.net/?f=0.0624%20molH_2%20%5Ctimes%20%5Cfrac%7B2molKAl%28OH%29_4%7D%7B3molH_2%7D%20%5Ctimes%20%5Cfrac%7B2molAl%28OH%29_3%7D%7B2molKAl%28OH%29_4%7D%20%5Ctimes%20%5Cfrac%7B1molAl_2%28SO_4%29_3%7D%20%7B2molAl%28OH%29_3%7D%20%5Ctimes%20%5Cfrac%7B2molAlum%7D%7B1molAl_2%28SO_4%29_3%7D%20%3D0.0416%20mol%20Alum)
The molar mass of alum is 474.38 g/mol. The mass corresponding to 0.0416 moles is:
![0.0416 mol \times \frac{474.38g}{mol} = 19.7 g](https://tex.z-dn.net/?f=0.0416%20mol%20%5Ctimes%20%5Cfrac%7B474.38g%7D%7Bmol%7D%20%3D%2019.7%20g)
Finally, we convert 19.7 grams to pounds using the conversion factor 1 lb = 454 g.
![19.7 g \times \frac{1lb}{454g} = 0.0434 lb](https://tex.z-dn.net/?f=19.7%20g%20%5Ctimes%20%5Cfrac%7B1lb%7D%7B454g%7D%20%3D%200.0434%20lb)
The pounds of alum produced when 0.26 g of hydrogen was produced are 0.0434 lb.
You can learn more about molar ratios here: brainly.com/question/15973092
Answer:
The independent variable influences change in the dependent variable whether the points on the scatterplot go up or down from left to right.
Explanation:
Answer: The correct answer is Francium and Fluorine.
Explanation:
The most vigorous chemical reaction will occur between the most reactive metal and most reactive non-metal.
Reactivity of metal is defined as the tendency of elements to loosing electrons easily. Reactivity of metals decreases as we move from left to right and increases as we move down in the group. Hence, the most reactive metal is Francium.
Reactivity of non-metals is defined as the tendency of the element to gain electrons easily. Reactivity of non-metals increases across a period and decreases as we move down in a group. Hence, the most reactive non-metal is Fluorine.
Therefore, the most vigorous chemical reaction will occur between Francium and Fluorine.