Given:
Mixture of vitamin water = 75% pure water & 25% concentrated vitamin drink.
To find:
Quantity of water to be added to 16 gallons of concentrated vitamin drink to prepare a tank of vitamin water.
Solution:
Let total amount of mixture be x.
25% of x = 16 gallons (from given information)
When 25% of x is 16 gallons, the remaining 75% of x will be calculated as below:
(16/25)*75 = 48
Answer: 75% of x = 48 gallons. This means 48 gallons pure water is required to be added to mixture to prepare a tank of vitamin water.
From the equation, we can see that the molar ratio between hydrogen and oxygen is:
2 : 1
Next, we determine the moles of hydrogen and oxygen that are actually present using:
moles = mass / Mr
Hydrogen:
moles = 4 / 2 = 2
Oxygen:
10/32 = 0.3125
Therefore, it is evident that the moles of oxygen present, 0.3125, are less than those that are required for 2 moles of hydrogen, which is 1. This makes oxygen the limiting reactant, which is the one that limits the completion of a reaction.
Answer:
d)
Explanation:
in one mole of phosphoric acid you have 3 mol hydrogen, 2 mol phosphorus, and 4 mol oxygen. just multiply everything by 2 and you get 2 mol of phosphoric acid
Answer:
ti determines which number of elements you got or have
Explanation:
Answer:
Li = M₂O
Na = M₂O₂
K = MO₂
Rb = MO₂
Cs = MO₂
Explanation:
Since the reactivity of alkali metals increases on moving down the group with the increase in atomic size, their reactivity towards oxygen increases on going down the from lithium to caesium.
Lithium being the least reactive reacts with oxygen in the air to give white lithium oxide, LiO₂.
Sodium reacts with excess oxygen when heated to form sodium peroxide, Na₂O₂
Potassium reacts with excess oxygen when heated to form potassium superoxide, KO₂
Rubidium reacts with excess oxygen when heated to form rubidium suproxide, RbO₂
Caesium reacts with excess oxygen when heated to form caesium superoxide, CsO₂
