Answer:
ΔG = -1.53 kJ/mol
Explanation:
The given reaction is:
3-Phosphoglycerate → 2-Phosphoglycerate
The standard Gibbs free energy, ΔG°=+4.40 kJ
[2-Phosphoglycerate] = 0.290 mM
[3-Phosphoglycerate] = 2.90 mM
Temperature T = 37 C = 310 K
The standard Gibbs free energy, ΔG° is related to the free energy change ΔG at a given temperature by the following equation:
In this reaction:
![\Delta G =\Delta G^{0}+RTln\frac{[2-Phosphoglycerate]}{[3-Phosphoglycerate]}](https://tex.z-dn.net/?f=%5CDelta%20G%20%3D%5CDelta%20G%5E%7B0%7D%2BRTln%5Cfrac%7B%5B2-Phosphoglycerate%5D%7D%7B%5B3-Phosphoglycerate%5D%7D)
![\Delta G = 4.40kJ/mol +0.008314 kJ/mol-K*310Kln\frac{[0.290]}{[2.90]}=-1.53 kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20G%20%3D%204.40kJ%2Fmol%20%2B0.008314%20kJ%2Fmol-K%2A310Kln%5Cfrac%7B%5B0.290%5D%7D%7B%5B2.90%5D%7D%3D-1.53%20kJ%2Fmol)
2.a)R b)R c)L d)L e)R f)L g)L
Top: The grasshopper population would begin to have a dramatic increase because of the lack of being eaten if the frogs disappeared and the snakes would decrease in population because of less food availability.
Bottom: All of the organisms in the food chain are equally as important because a drastic change would occur if one disruption was made.
Answer: the boiling point is = 137.325°C
Explanation:
From the formula: ∆Tb= Kb*m
From the question, Kb= 0.95, m= 27.5, T1= 111.2°C
Substitute into ∆Tb= Kb*m
∆Tb= 0.95*27.5= 26.125
∆Tb= T2-T1
Hence
T2- 111.2=26.125
T2= 26.125+ 111.2= 137.325°C
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