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Sphinxa [80]
3 years ago
15

Funtions of a fuse box​

Physics
1 answer:
rodikova [14]3 years ago
7 0
The function of the fuse-box or breaker-box or main or sub panel is to distribute electricity from an incoming supply to different branch circuits to supply receptacles, light fixtures and hardwired electrical appliance with electricity. ... And a row of breakers or fuses connected to the bus-bars .
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Assortative mating changes ______ frequencies but does not change ______ frequencies.
andrew-mc [135]

Allele frequencies are unaffected by assortative mating, but genotype frequencies .

<h3>Assortative mating: </h3>

Individuals with similar phenotypes and genotypes mate with others more frequently than is anticipated under a random mating pattern in assortative mating, which is a mating pattern and a type of sexual selection.

<h3>Frequencies of genotypes:</h3>

A population's genotype frequency is calculated by dividing the number of people having a particular genotype by the overall population size. The genotype frequency in population genetics is the frequency or ratio (i.e., 0 f 1) among genotypes inside a population.

<h3>The frequency for alleles in biology:</h3>

The term "allele frequency" describes the prevalence of an allele in a population. It is calculated by calculating the number of times the allele occurs in the population and dividing by the sum of all the gene copies.

To know more about Assortative mating visit:

brainly.com/question/28238408

#SPJ4

4 0
1 year ago
While playing basketball in PE class, Logan lost his balance after making a lay-up and colliding with the padded wall behind the
olga2289 [7]

Answer:

a.) F = 3515 N

b.) F = 140600 N

Explanation: given that the

Mass M = 74kg

Initial velocity U = 7.6 m/s

Time t = 0.16 s

Force F = change in momentum ÷ time

F = (74×7.6)/0.16

F = 3515 N

b.) If Logan had hit the concrete wall moving at the same speed, his momentum would have been reduced to zero in 0.0080 seconds

Change in momentum = 74×7.6 + 74×7.6

Change in momentum = 562.4 + 562.4 = 1124.8 kgm/s

F = 1124.8/0.0080 = 140600 N

6 0
3 years ago
A 3.0-kilogram cart possesses 96 joules of kinetic<br> energy. Calculate the speed of the car.
Dvinal [7]

Answer:

8.0 m/s

Explanation:

KE = ½ mv²

96 J = ½ (3.0 kg) v²

v = 8.0 m/s

5 0
3 years ago
How do you think the body deals with consuming a lot more<br> calories than are burnt?
natali 33 [55]

Answer:

The body stores it as fat

Explanation:

3 0
3 years ago
Read 2 more answers
A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is applied. A 0.500-kg particle res
garri49 [273]

Answer:

ω = 22.36 Hz

f = 3.56 Hz

T = 0.28 s.      

Explanation:

a) The angular frequency (ω), can be calculated using the following equation:

\omega = \sqrt{\frac{k}{m}} = \sqrt{\frac{F}{x*m}}  

<u>Where:</u>

<em>k: is the spring constant = F/x</em>

<em>m: is the mass of the particle = 0.500 kg</em>

<em>F: is the force applied = 7.50 N       </em>

<em>x: is the displacement = 3.00 cm = 0.03 m </em>            

\omega = \sqrt{\frac{7.50 N}{0.03 m*0.500 kg}} = 22.36 s^{-1} = 22.36 Hz    

Therefore, the angular frequency of the motion is 22.36 Hz.

b) To find the frequency (f) we can use the next equation:

f = \frac{\omega}{2 \pi} = \frac{22.36 Hz}{2 \pi} = 3.56 Hz

Hence, the frequency of the motion is 3.56 Hz.

c) The period (T) is equal to:

T = \frac{1}{f} = \frac{1}{3.56 Hz} = 0.28 s

Therefore, the period of the motion is 0.28 s.

I hope it helps you!

4 0
3 years ago
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