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Sphinxa [80]
3 years ago
15

Funtions of a fuse box​

Physics
1 answer:
rodikova [14]3 years ago
7 0
The function of the fuse-box or breaker-box or main or sub panel is to distribute electricity from an incoming supply to different branch circuits to supply receptacles, light fixtures and hardwired electrical appliance with electricity. ... And a row of breakers or fuses connected to the bus-bars .
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A force of 1.5 × 102 N is exerted on a charge of 1.4 × 10–7 C that is traveling at an angle of 75° to a magnetic field.
Marysya12 [62]

Option (B) is correct.The magnetic field strength=8.5 x 10² T

Explanation:

the magnetic force Fm is given by

Fm= q V B sinθ

q= charge=1.4 x 10⁻⁷ C

v= velocity= 1.3 x 10⁶ m/s

B= magnetic field strength

Fm= magnetic force= 1.5 x 10² N

θ=75°

so 1.5 x 10²=(1.4 x 10⁻⁷) (1.3 x 10⁶ ) (B) sin75

B=8.5 x 10² T

6 0
3 years ago
Read 2 more answers
A mercury in barometer shows a height of 70cm.What height would be shown in the barometer at the same place if water density 1.0
Pie

Answer:

P = d g h      pressure due to density of liquid of height h

d1 g h1 = d2 g h2       since P1 equals P2

d1 h1 = d2 h2      and the density of Hg is 13.6 times that of water

h2 = (d1 / d2) * h1 = 13.6 * 70 cm =  952 cm or 9.52 m

8 0
3 years ago
A has the magnitude 14.4 m and is angled 51.6° counterclockwise from the positive direction of the x axis of an xy coordinate sy
Ad libitum [116K]

Answer:

à in unit vector notation = 12.26485i + 7.54539j

B in unit vector notation = 16.3516i + 3.11529j

Explanation:

The detailed steps and calculation is shown in the attachment.

7 0
3 years ago
Question 2 10
ss7ja [257]
B Ik it all just know who they’ll you
8 0
2 years ago
A wooden plaque is in the shape of an ellipse with height 30 centimeters and width 22 centimeters. Find an equation for the elli
Volgvan

Answer:

Explanation:

height of Ellipse =30 cm  

i.e. 2 a=30

Width of Ellipse =22 cm

i.e. 2 b=22

Equation of a vertical Ellipse is

\frac{x^2}{b^2}+\frac{y^2}{a^2}=1

a=15 ,b =11

\frac{x^2}{11^2}+\frac{y^2}{15^2}=1

at y=4 cm

\frac{x^2}{11^2}+\frac{4^2}{15^2}=1  

x=\frac{11}{15}\times \sqrt{15^2-4^2}

x=10.6 cm  

5 0
3 years ago
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