All categories

3 years ago

The headlights of a typical truck are powered by a 12 V battery. What current do they draw if the resistance is 4.8 ohms?

Physics

2 answers:

mestny [16]3 years ago

7 0

Answer:

2.5

Explanation:

USA Test prep

vodomira [7]3 years ago

6 0

Solve this using Olm's law, which relates current (C), voltage (V), and resistance (R). Olm's law says:
$I \: (current ) ={\frac {V \: (voltage) }{R\:(resistance)}}$

We are told that voltage, V = 12V, and resistance, R = 4.8 <span>Ω. Plug these values into the equation and solve for current:
</span> $I = \frac{V}{R}\\
I = \frac{12}{4.8}\\
I = 2.5A

$
<span>-----
Answer: Current = 2.5 Amperes</span>

You might be interested in

What are two parts of an atom

seraphim [82]

Answer:

Nucleus And electron cloud

Explanation:

Hope this helps

7 0

3 years ago

How do you think that changing the mass of the pendulum bob will affect the period of the pendulum swing?

myrzilka [38]

(Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.)

5 0

3 years ago

A water main pipe of diameter 10 cm enters a house 2 m below ground. A smaller diameter pipe carries water to a faucet 5 m above

Lemur [1.5K]

Explanation:

Given that,

Diameter = 10 cm

Distance = 2 m

Speed $v_{1}= 2\ m/s$

Speed $v_{2}=7\ m/s$

Pressure in main pipe $P_{1}=2\times10^{5}\ Pa$

(I). We need to calculate the diameter

Using equation of continuity

$Av_{1}=Av_{2}$

$\pi(\dfrac{d_{1}}{2})^2\times v_{1}=\pi(\dfrac{d_{2}}{2})^2\times v_{2}$

$(\dfrac{10}{2})^2\times2=(\dfrac{d_{2}}{2})^2\times7$

$d_{2}=\sqrt{\dfrac{25\times2\times4}{7}}$

$d_{2}=5.345\ cm$

(II). We need to calculate the pressure the gauge pressure

Using Bernoulli equation

$P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho g h_{2}$

$P_{2}=P_{1}+\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)-\rho g(h_{1}-h_{2})$

$P_{2}=2\times10^{5}+\dfrac{1}{2}\times1000(4-49)-1000\times 9.8\times(5)$

$P_{2}=1.28500\times10^{5}\ Pa$

(III). If it is possible to carry water to a faucet 17 m above ground,

Using Bernoulli equation

$P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh=P_{3}+\dfrac{1}{2}\rho v_{3}^2+\rho g h_{3}$

$P_{3}=P_{1}+\dfrac{1}{2}\rho v_{1}^2-\rho g(h_{1}-h_{3})$

Here, $h_{3}=0$

Put the value in the equation

$P_{3}=2\times10^{5}+\dfrac{1}{2}\times1000\times4-1000\times 9.8\times17$

$P_{3}=3.5400\times10^{5}\ Pa$

Hence, This is required solution.

7 0

3 years ago

Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz t

maw [93]

Answer:

3.117 m

Explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

$L_1=\frac{L-A}{2}$

where A = $\frac{Velocity ofthe sound (V)}{Frequency (F)}$

we have:

$L_1=\frac{L-\frac{V}{F} }{2}$

$L_1=\frac{6.69-\frac{343}{750} }{2}$

$L_1=\frac{6.69-0.457 }{2}$

$L_1=\frac{6.233 }{2}$

$L_1= 3.1165 m$

$L_1=3.117 m$

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m

3 0

3 years ago

Which velocity graph shows the car moving toward the right (away from the origin) at a steady (constant) velocity?

slega [8]

Explanation:

$\text{Velocity is defined as the average displacement per unit time.}$

$\text{Since the car is moving at a steady velocity, the velocity does not change over time, it shows a horizontal line on the }v-t\text{ graph}$

$\text{Therefore, only option 2,5,8 matches this requirement.}$

$\text{Since the car is moving to the right, which is defined as the positive direction in this question, the velocity (}v\text{) is also positive.}$

$\text{Therefore, only option 5 is correct.}$

6 0

3 years ago