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belka [17]
3 years ago
8

Anyone want to be f-r-i-e-n-d-s? ^^ (You may answer for fr/ee points! <3)

Physics
2 answers:
monitta3 years ago
5 0

Answer:

 

Explanation:

Nuetrik [128]3 years ago
3 0

Answer:

YESSSS!

Explanation:

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An aluminum wire has a resistance of 7.00 Ω at 30.0°C. Determine its resistance (in Ω) at 430°C. The temperature coefficient of
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Answer:

17.92 Ω

Explanation:

R₀ = Initial resistance of the aluminum wire at 30.0°C = 7.00 Ω

R = resistance of the aluminum wire at 430.0°C = ?

α = temperature coefficient of resistivity for aluminum = 3.90 x 10⁻³ °C⁻¹

ΔT = Change in temperature = 430 - 30 = 400 °C

Resistance of the wire is given as

R = R₀ (1 + α ΔT)

R = (7) (1 + (3.90 x 10⁻³) (400))

R = 17.92 Ω

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I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)

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