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kondor19780726 [428]
3 years ago
15

Elements, Compounds,& Mixtures,

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

1. Elements: F, H, E

2. Compounds: A, D, I

3. Mixtures: B, C, G

Explanation:

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3 years ago
A chemist prepares a solution of barium acetate by measuring out of barium acetate into a volumetric flask and filling the flask
leonid [27]

The given question is incomplete. The complete question is :

A chemist prepares a solution of barium acetate by measuring out 32 g of barium acetate into a 350 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's barium acetate solution. Round your answer to significant digits.

Answer:  The concentration of barium acetate solution is 0.375 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

moles of Ba(CH_3COO)_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{32g}{255g/mol}=0.125mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.125\times 1000}{350ml}

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Therefore, the concentration of solution is 0.375 mol/L

8 0
3 years ago
How can I differentiate between Ionic compounds, molecular compounds, and acids given only the formula? I need to be able to fin
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Iodine chloride, ICl, can be made by the following reaction between iodine, I2, potassium iodate, KIO3, and hydrochloric acid.
Vadim26 [7]
The balanced chemical reaction is:

<span>2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O 
</span>
We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.

28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2
6 0
3 years ago
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