Answer:
The formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
Explanation:
Iron (ii) ions, Fe²⁺ have a positive charge of +2. Chromate ions, CrO₄²⁻, on the other hand have a positive charge of -2. When iron (ii) ions and chromate ions combine two form a compound, each ion will contribute a mole of ion towards the formation of the compound. This is in line with the idea that a compound carries no charge. The positive charge (+2) of the iron (ii) ions are balanced by the negative charge of the chromate ions as shown mathematically as follows;
+2 + (-2) = 0; i.e. Fe²⁺ + CrO₄²⁻ = FeCrO₄
Therefore, the formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
Yes , it does become massive and it also becomes heavier.
Answer:
C. 2O₃ ⇌ 3O₂
Explanation:
Kp is the equilibrium constant calculated from the partial pressures of a gas-phase reaction equation.
For a general gas-phase reaction aA + bB ⇌ nC + xD
the expression for the Kp = (pC)ⁿ(pD)ˣ / (pA)ᵃ(pB)ᵇ
where pA = partial pressure of A; pB = partial pressure of B; pC = partial pressure of C; pD = partial pressure of D
From the given reaction in equilibrium; N₂ + 3H₂ ⇌ 2NH₃
Kp = (pNH₃)² / (pN₂)¹ * (pH₂)³ = 4/7
(pNH₃)² / (pN₂)¹ * (pH₂)³ = (2)²/ (1)¹ * (3)³
Therefore, number of mole of reactants and products is equivalent to partial pressure.
A. 2SO₂ ⇌ O₂ + 2SO₃
pSO₂ = 2, pO₂ = 1, pSO₃ = 2,
Kp = 2²/ (2² * 1²) = 4/4 = 1
B. N₂O₄ ⇌ 2NO₂
pN₂O₄ = 1, pNO₂ = 2
Kp = 2²/1² = 4
C. 2O₃ ⇌ 3O₂
pO₃ = 2, pO₂ = 3
Kp = 3³/2² = 27/4
D. PCl₅ ⇌ PCl₃ + Cl₂
pPCl₅ = 1, pPCl₃ = 1, pCl₂ = 1
Kp = (1¹ * 1¹) / 1¹ = 1
