ATOMIC NUMBER OF FLOURINE = 9
ELECTRONIC CONFIGURATION OF FLOURINE = 1s2 , 2s2, 2p5
HOPE IT MAY HELP U
<span>If the volume of a sample of water is 2.5 milliliters, the volume of this sample in liters is A.) 2.5 x 10^-3 L. 1 mL = 1 x 10^-3 L. 2.5 mL = x L. Make a proportion. 1 mL : 1 x 10^-3 L = 2.5 mL : x. x = 2.5 mL * 1 x 10^-3 L : 1 mL. x = 2.5 x 10^-3 L. Therefore, 2.5 mL = 2.5 x 10^-3 L.</span>
Answer:
24.12 days
Explanation:
First off, let's find out how many decays the compound ; iodine131 undergoes to get to 17.5 percent of its original value.
Half life is simply the time required for a quantity to reduce to half of its initial value.
The half-life of iodine-131 is 8.04 days.
100% - 50% (First Half life)
50% - 25% (Second Half life)
25% - 17.5% (Third Half life)
This mwans i would take three halff lives;
Time requred = 3 * Half life = 3 * 8.04 days = 24.12 days
