All categories

2 years ago

What is the arrangement of water in the gaseous liquid and solid states

1 answer:

6 0

In the gaseous state, the molecules are spread very widely apart from one another and are free to move about. If placed in a container, the molecules will occupy the volume of the container and take its shape as well.

The molecules in the liquid state are closer than in the gaseous state and less free to move about. They are in layers that slide over one another, allowing the substance to flow. If placed in a container, the liquid water will take its shape but not the volume.

The molecules in the solid state are fixed in position, only able to vibrate about their fixed points. The structure formed is rigid, it does not flow and its shape and volume are fixed.

You might be interested in

ANSWER THE QUESTION BELOW FOR BRAINLEST AND 10 POINTS

Katarina [22]

C :) shshdjehwjdjdjsjsjsbsbbsdp

5 0

2 years ago

Read 2 more answers

Which of the following environmental risks is most likely to lead to digestive health issues?

xz_007 [3.2K]

You haven’t listed answer choices for this question

5 0

3 years ago

Read 2 more answers

g Phosphorus -32 is a commonly used radioactive nuclide in biochemical research, particularly in studies of nucleic acids. The h

Setler79 [48]

Answer:

6.88 mg

Explanation:

Step 1: Calculate the mass of ³²P in 175 mg of Na₃³²PO₄

The mass ratio of Na₃³²PO₄ to ³²P is 148.91:31.97.

175 mg g Na₃³²PO₄ × 31.97 g ³²P/148.91 g Na₃³²PO₄ = 37.6 mg ³²P

Step 2: Calculate the rate constant for the decay of ³²P

The half-life (t1/2) is 14.3 days. We can calculate k using the following expression.

k = ln2/ t1/2 = ln2 / 14.3 d = 0.0485 d⁻¹

Step 3: Calculate the amount of P, given the initial amount (P₀) is 37.6 mg and the time elapsed (t) is 35.0 days

For first-order kinetics, we will use the following expression.

ln P = ln P₀ - k × t

ln P = ln 37.6 mg - 0.0485 d⁻¹ × 35.0 d

P = 6.88 mg

3 0

2 years ago

Convert 11.03 moles of calcium nitrate to grams

hichkok12 [17]

Im pretty sure the answer is <span> 0.01218859659g

not 100% sure tho so please consult someone else b4 answering
i hope this helps!!</span>

6 0

3 years ago

Read 2 more answers

Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these were decomposed the sulfur dioxide produce

Zinaida [17]

Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

Explanation : Given,

Mass of oxygen in sulfur dioxide = 3.49 g

Mass of sulfur in sulfur dioxide = 3.50 g

Mass of oxygen in sulfur trioxide = 9.00 g

Mass of sulfur in sulfur trioxide = 6.00 g

Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur dioxide = $\frac{3.49}{3.50}=0.997g$

and,

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}$

Mass of oxygen per gram of sulfur for sulfur trioxide = $\frac{9.00}{6.00}=1.5g$

Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

8 0

3 years ago