All categories

3 years ago

How so you kniw when you need to use ate, ide, and ite

2 answers:

7 0

-ide is used for non-metal compounds generally. For example, Chlorine forms a chloride ion, so NaCl is Sodium Chloride. -ate and -ite are commonly used for polyatomic ions of Oxygen. -ate is used for the ion that has the largest number of Oxygen atoms. the -ite would be used for the ion with the smaller. NO2 and NO3 are known as Nitrite and Nitrate respectively. Nitrite has a smaller number of oxygen atoms so when added to an element it will be _ Nitrite. On the other than, Nitrate has a larger number of Oxygen atoms so when added to an element it is _ Nitrate.

Hope that helps!

yaroslaw [1]3 years ago

3 0

Ate is probably at the end of a polyatomic ion, ide is at the end of a compound and it's is also on the end of a polyatomic ion just one that has had its charges changed

You might be interested in

If a substance evaporates easily, it is said to be _______. volatile condensing crystallized changing pigmentation

Paraphin [41]

The correct answer is A.) Volatile. please mark brainliest (:

4 0

4 years ago

Read 2 more answers

What are the possible values of ml for l=2<br>

Marrrta [24]

Answer:

-2, -1, 0, 1, 2

Explanation:

There are four types of quantum numbers;

1) Principal quantum number (n)

2) Azimuthal quantum number (l)

3) magnetic quantum number (ml)

4) Spin quantum number (s)

The azimuthal quantum number (l) describes the orbital angular momentum and shape of an orbital while the magnetic quantum number shows the projections of the orbital angular momentum along a specified axis. This implies that the magnetic quantum number shows the orientation of various orbitals along the Cartesian axes. The values of the magnetic quantum number ranges from -l to + l

For l= 2, the possible values of the magnetic quantum number are; -2, -1, 0, 1, 2

5 0

3 years ago

2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2

nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with $H_2$ to form $CH_4$ and $H_2O$ . balanced reaction is:

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

No. of moles of CO = 0.800 mol

No. of moles of $H_2$ = 2.40 mol

Volume = 8.00 L

Concentration = $\frac{Moles}{Volume\ in\ L}$

Concentration of CO = $\frac{0.800}{8.00} = 0.100\ mol/L$

Concentration of $H_2$ = $\frac{2.40}{8.00} = 0.300\ mol/L$

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

Initial 0.100 0.300 0 0

equi. 0.100 -x 0.300 - 3x x x

It is given that,

at equilibrium $H_2O (x)$ = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium $H_2$ = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium $CH_4$ = 0.0386 M

$Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}$

$Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90$

8 0

4 years ago

What is the mass of 0.46 mol of MgCl2

Ronch [10]

Answer:

43.7

Explanation:

mole is equal mass concentration/ moler mass of MgCl²

8 0

4 years ago

What mass of mgo is produced from 2.00 moles of mg ? Mg +02 mgo

Vanyuwa [196]

Chemical Reactions and Moles of Reactants and Products
That is, it requires 2 moles of magnesium and 1 mole of oxygen to produce 2 moles of magnesium oxide. If only 1 mole of magnesium was present, it would require 1 ÷ 2 = ½ mole of oxygen gas to produce 2 ÷ 2 = 1 mole magnesium oxide.

3 0

3 years ago