When utilizing a transmission electron microscope, why is it necessary to stain the specimen with heavy metal salts?
2 answers:
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The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.
<h3>What is the half-life of a radioactive material?</h3>The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.
The half-life, , the age, t, and amount remaining,
, of a radioactive material are related by the formula below:
Half-life of carbon-14 = 6000 years
For the Egyptian papyrus with 63% of its original carbon-14 atoms:
For the Aboriginal charcoal with 22% of its original carbon-14 atoms:
For the Mayan headdress with 79% of its original carbon-14 atoms:
Neanderthal skull with 3% of its original carbon-14 atoms:
Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.
Learn more about half-life at: brainly.com/question/26689704
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Answer:
See explanation below
Explanation:
The question is incomplete. However in picture 1, you have the starting materials and the structure of the product, which you miss in this part.
Now, in picture 2, you have the starting reactant and the product, and the mechanism that is taking place here.
First, all what we have here is an acid base reaction. In the first step, we are using the acid medium to convert the reactant into an alcohol. The bromine there, is not leaving the molecule yet, because it's neccesary for the next step. The starting reactant is an alkene, in that way, we can convert the reactant in the first step into a secondary alcohol. In other words, the first reaction is a alkene hydration.
In the second step, we use a strong base. You may say this is a strong nucleophile and will do a Sn2 reaction to form another alcohol there, but it's not the case, because, before any kind of reaction happens, the priority here is always the acid base, so the base will react with the acidic hydrogen. In this case, it will substract an hydrogen from the OH. When this happens, the lone pair will do an auto condensation here, and attacks the bromine in the molecule. In this way, the molecule will become a cyclomolecule, and that way it form the final product.
See picture 2, for mechanism
