Answer:
b. 1.5 atm.
Explanation:
Hello!
In this case, since the undergoing chemical reaction suggests that two moles of A react with one moles of B to produce two moles of C, for the final pressure we can write:
![P=P_A+P_B+P_C](https://tex.z-dn.net/?f=P%3DP_A%2BP_B%2BP_C)
Now, if we introduce the stoichiometry, and the change in the pressure
we can write:
![P=1.0-2x+1.0-x+2x](https://tex.z-dn.net/?f=P%3D1.0-2x%2B1.0-x%2B2x)
Nevertheless, since the reaction goes to completion, all A is consumed and there is a leftover of B, and that consumed A is:
![x=\frac{1.0atm}{2}=0.5atm](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1.0atm%7D%7B2%7D%3D0.5atm)
Thus, the final pressure is:
![P=1.0-2(0.5)+1.0-(0.5)+2(0.5)\\\\P=1.5atm](https://tex.z-dn.net/?f=P%3D1.0-2%280.5%29%2B1.0-%280.5%29%2B2%280.5%29%5C%5C%5C%5CP%3D1.5atm)
Therefore the answer is b. 1.5 atm.
Best regards!
Answer:
0.5 M
Explanation:
From the question given above, the following data were obtained:
Mass of NaOH = 80 g
Volume of solution = 4 L
Molarity =?
Next, we shall determine the number of mole in 80 g of NaOH. This can be obtained as follow:
Mass of NaOH = 80 g
Molar mass of NaOH = 23 + 16 + 1
= 40 g/mol
Mole of NaOH =?
Mole = mass / molar mass
Mole of NaOH = 80 / 40
Mole of NaOH = 2 moles
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Mole of NaOH = 2 moles
Volume of solution = 4 L
Molarity =?
Molarity = mole / Volume
Molarity = 2/4
Molarity = 0.5 M
Therefore, the molarity of the solution is 0.5 M.
Hello, I would like to help you, but I really don't understand the question
Answer:
The answer to your question is: solvent
Explanation:
Solvent is a component in a solution that is present in the highest amount and is able to dissolve the other or others components.
Answer:
The answer to your question is Q = 355.64 J
Explanation:
Data
Heat = Q = ?
Temperature 1 = T1 = 20°C
Temperature 2 = T2 = 37°C
mass = m = 5 g
Specific heat = Cp = 4.184 J/g°C
Formula
Q = mCp(T2 - T1)
-Substitution
Q = (5)(4.184)(37 - 20)
-Simplification
Q = (5)(4.184)(17)
-Result
Q = 355.64 J