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Mekhanik [1.2K]
3 years ago
5

1. AA, AAA, C and D cells all deliver the same voltage( 1.5V) when the batteries are fully charged. However,as the size of the b

attery increases, the amount of current that can be deliveredby the battery also increases. What is the difference inside these bateries that accounts for the increase in current with size? Expalin.
2. The overall reaction for alkaline battery is given by
Zn(s)+ MnO2(s)+H2O(l)--> ZnO(s) + Mn(OH)2(s)
Does matallic zinc functon as the anode or the cathode in this system?
Chemistry
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

A. The increase in size of the battery results in a smaller internal resistance and hence, a larger current delivery.

B. Zinc serves as the anode

Explanation:

A. The current that a battery can deliver is affected by the internal resistance of the battery.

The internal resistance resistance, r, is the resistance to flow of current within the battery. The smaller the internal resistance for a given emf, the more current and the more power the source can supply.

The relationship between current, I, emf, E, the external load ,R, and internal resistance is given by the equation:

I = E / (R + r)

The bigger the size of a battery, the smaller its internal resistance and thus, the larger the current the battery can deliver.

B. In a battery, the cathode is reduced by accepting electrons from the anode, while the anode is oxidized to zinc ion by giving up its electrons to the cathode.

From the equation of the reaction, metallic zinc is oxidized by giving up two electron to the cathode.

Zn(s) ----> Zn2+ + 2e-

Therefore, metallic zinc serves as the anode.

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Homogeneous Reactions. At equilibrium, the rate of the forward and reverse reaction are equal, which is demonstrated by the arrows. The equilibrium constant, however, gives the ratio of the units (pressure or concentration) of the products to the reactants when the reaction is at equilibrium.

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A bike rider approaches a hill with a speed of 8.5 m/s. The total mass of the bike and the rider is 85 kg. Find the kinetic ener
krek1111 [17]

KE=3070.625 J

Height = 3.686 m

<h3>Further explanation</h3>

mass of bike+rider=85 kg

velocity = 8.5 m/s

\tt KE=\dfrac{1}{2}mv^2\\\\KE=\dfrac{1}{2}\times 85\times 8.5^2\\\\KE=3070.625~J

Conservation of energy :

(KE+PE)₁ (downhill) = (KE+PE)₂ (up the hill)

PE₁=0⇒h=0

KE₂=0⇒v=0(stop), so equation becomes :

KE₁=PE₂

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Problem PageQuestion Sulfuric acid is essential to dozens of important industries from steelmaking to plastics and pharmaceutica
Feliz [49]

The question is incomplete, here is the complete question:

Sulfuric acid is essential to dozens of important industries from steel making to plastics and pharmaceuticals. More sulfuric acid is made than any other industrial chemical, and world production exceeds  2.0×10¹¹ kg per year.

The first step in the synthesis of sulfuric acid is usually burning solid sulfur to make sulfur dioxide gas. Suppose an engineer studying this reaction introduces 1.8 kg of solid sulfur and 10.0 atm of oxygen gas at 650°C  into an evacuated 50.0 L tank. The engineer believes Kp = 0.099 for the reaction at this temperature.

Calculate the mass of solid sulfur he expects to be consumed when the reaction reaches equilibrium. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of solid sulfur that will be consumed is 19. grams

<u>Explanation:</u>

The chemical equation for the formation of sulfur dioxide gas follows:

                    S(s)+O_2\rightarrow SO_2(g)

<u>Initial:</u>                   10.0

<u>At eqllm:</u>              10-x         x

The expression of K_p for above equation follows:

K_p=\frac{p_{SO_2}}{p_{O_2}}

We are given:

K_p=0.099

Putting values in above expression, we get:

0.099=\frac{x}{10-x}\\\\x=0.901atm

Partial pressure of sulfur dioxide = x = 0.901 atm

To calculate the number of moles, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the sulfur dioxide gas = 0.901 atm

V = Volume of the gas = 50.0 L

T = Temperature of the gas = 650^oC=[650+273]K=923K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of sulfur dioxide gas = ?

Putting values in above equation, we get:

0.901atm\times 50.0L=n\times 0.0821\text{ L. atm}mol^{-1}K^{-1}\times 923K\\\\n=\frac{0.901\times 50.0}{0.0821\times 923}=0.594mol

By stoichiometry of the reaction:

1 mole of sulfur dioxide gas is produced from 1 mole of sulfur

So, 0.594 moles of sulfur dioxide gas will be produced from = \frac{1}{1}\times 0.594=0.594mol of sulfur

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of sulfur = 0.594 moles

Molar mass of sulfur = 32 g/mol

Putting values in above equation, we get:

0.594mol=\frac{\text{Mass of sulfur}}{32g/mol}\\\\\text{Mass of sulfur}=(0.594mol\times 32g/mol)=19.008g

Hence, the mass of solid sulfur that will be consumed is 19. grams

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Answer:

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where in liquid the shape will be different depending on the container

and in gas state the shape and volume are not definite

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