Answer:
The question is incomplete as some details are missing. Here is the complete question ; A chemist adds 45.0mL of a 0.434M copper(II) sulfate CuSO4 solution to a reaction flask. Calculate the mass in grams of copper(II) sulfate the chemist has added to the flask. Round your answer to 2 significant digits
Explanation:
The step by step explanation is as shown in the attachment
Answer:
6,97x10⁻³ gallons
Explanation:
pH is defined as:
pH = -log [H⁺]
Thus, you need to have, in the end:
10⁻⁷ = [H⁺]
And you have, in the first:
= [H⁺]
The volume of swimming pool is:
700'000 galllons × = 2649787 L
Thus, the moles of H⁺ in the first and in the end are:
First:
× 2649787L = 1,24x10⁻³ moles
End:
× 2649787L = 0,265 moles
Thus, the moles of H⁺ you need to add are:
0,265 - 1,24x10⁻³ = <em>0,26376 moles</em>
These moles comes from 10M HCl, thus, the volume in gallons you need to add are:
=
<em>6,97x10⁻³ gallons</em>
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I hope it helps!