Answer:
1.![9000kgm/s](https://tex.z-dn.net/?f=9000kgm%2Fs)
2.![258,000kgm/s](https://tex.z-dn.net/?f=258%2C000kgm%2Fs)
Explanation:
1.Momentum is given as the product of mass by velocity of an object.
Momentum,![p=mv](https://tex.z-dn.net/?f=p%3Dmv)
m=1,500kh, v=6m/s
![p=1500*6\\p=9000kgm/s](https://tex.z-dn.net/?f=p%3D1500%2A6%5C%5Cp%3D9000kgm%2Fs)
2.Momentum,![p=mv](https://tex.z-dn.net/?f=p%3Dmv)
m=7800kg, v=30m/s
![p_1=7800*30\\p_1=234,000kgm/s\\](https://tex.z-dn.net/?f=p_1%3D7800%2A30%5C%5Cp_1%3D234%2C000kgm%2Fs%5C%5C)
new mass=7800+800=8600
As mass is increased, so does the resultant velocity as mass is directly proportional to velocity.
![p_2=8600*30\\p_2=258,000kgm/s](https://tex.z-dn.net/?f=p_2%3D8600%2A30%5C%5Cp_2%3D258%2C000kgm%2Fs)
Answer:
A) if the system is isothermal then all the heat added to the system will be used to do work (since none is used to raise the temperature of the gas). The heat added will be equal to the work done = 340 J
B) change in internal energy of the system of the process is isothermal will be zero, since there is no rise in temperature.
C) an adiabatic process is one involving no heat loss or gain through the system, Therefore heat gain will be zero
D) if the process is adiabatic then there is no heat loss or gain through the system and hence there is no change in temperature. Change in internal energy will be zero
E) if the process is isobaric then, there is no work done and the total heat to the system is equal zero
F) if there is no work done, and no heat added, then the internal energy will be equal zero.
Answer:
a)CH₄, BH₃, and CCl₄
Explanation:
<u>London dispersion forces:-
</u>
The bond for example, in the molecule is F-F, which is non-polar in nature because the two fluorine atoms have same electronegativity values.
The intermolecular force acting in the molecule are induced dipole-dipole forces or London Dispersion forces / van der Waals forces which are the weakest intermolecular force.
Out of the given options, H₂O , NH₃ exhibits hydrogen bonding which is:-
<u>Hydrogen bonding:-
</u>
Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.
Thus option B and C rules out.
<u>Hence, the correct option which represents the molecules which would exhibit only London forces is:- a)CH₄, BH₃, and CCl₄</u>
Answer:
0.025536g
Explanation:
no. of mole = mass/Mr
mass = Mr × no. of mole
= [23 + 1 + 12 + 3(16)] × 3.04×10^-4
= 0.025536g
= 0.0255g (3 significant figures)