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3 years ago

Which feature signifies to astronomers that a distant star is part of a planetary system

Physics

2 answers:

Romashka-Z-Leto [24]3 years ago

8 0

Because it also can be apart of the milky way galaxy

liq [111]3 years ago

6 0

Answer: a) The star periodically dims.

A star is the body of gas in which nuclear fusion of gases like helium and hydrogen takes place due to this reason the star glows or dim. Star gets the ability to generate light because of this nuclear fusion which cannot be observed in planets although the process of generation of star and planet is the same. In distantly located star under observation, it's luminosity ( the property of emitting lighting) is controlled by size of the star, the larger the size of the star it will have greater surface area the more profound will be the nuclear fusion in it and more light will be emitted. Second factor is the gaseous interaction of gases in and around the star and their temperature which causes the change in the light which has to pass through a layer of these gases. Therefore, the distant star observed will show light fluctuations.

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Which represent correct variations of the formula for speed? Check all that apply. t = d/s s = d/t t = s/d s = dt d = st d = s/t

vivado [14]

S=d/t this is because speed is just the measurement of time and distance

8 0

3 years ago

Read 2 more answers

The amount of work done by two boys who apply 200 N of force in an

Aleksandr [31]

The amount of work done by two boys who apply 200 N of force in an unsuccessful attempt to move a stalled car is 0.

Answer: Option B

<u>Explanation: </u>

Work done is the measure of work done by someone to push an object from its present position. We can also define work done as the amount of forces needed to move an object from its present position to another position. So the amount of work done is directly proportionate to the product of forces acting on the object and the displacement of the object.

$\text { Work done }=\text { Force } \times \text { displacement }$

So in this present case, as the two boys have done an unsuccessful attempts to push a stalled car so that means the displacement of the car is zero as there is no change in the position of the car. But they have applied a force of 200 N each. So the amount of work done will be

$\text { Work done }=200 \mathrm{N} \times 0=0$

Thus, the amount of work done by two boys will be zero due to their unsuccessful attempt to move a stalled car.

8 0

3 years ago

True or false

Readme [11.4K]

Answer:

true

Explanation:

I believe the answer i chose because the earths atmosphere is mostly made up of different things that causes the earth to interact with human life and also interacts with what's in the atmosphere like energy oxygen carbon dioxide and all the stuff like that i hope its right.

6 0

3 years ago

A series-parallel circuit consists of two parallel circuits connected in series across a 45-V source. One parallel branch consis

musickatia [10]

Answer:

The answer to the question is

The current through R4 = 0.5865 mA

Explanation:

To solve this we list out the known thus

Voltage source = 45-V

Firsrt parallel circiuit has resistances of R1 = 17 kΩ and R2 = 23 kΩ

Second parallel circiuit has resistances of R3 = 45 kΩ and R4 = 55 kΩ

we first find the current flowing in the circuit by finding thr sum of the total resistance in eah parallel circuit

Firsrt parallel circiuit, for circuit in parallel, sum of resistance 1/RT1 = 1/ R1 + 1/R2 = 1/17+1/23 = 0.1023017 therefore RT1 = 1/0.1023017 = 9.775 kΩ

Similarly we have for the second parallel circuit 1/RT2 = 1/R3 + 1/R4

= 1/45 + 1/55 = 0.0404 Hence RT2 = 1/0.0404 = 24.75 kΩ

This means that the 9.775 kΩ and the 24.75 kΩ are in series hence total resistance of the circuit = sum of all resistances in series

= 9.775 kΩ + 24.75 kΩ = 34.525 kΩ

However current, I is given by V/R = 45-V/34.525 kΩ = 1.303 × 10⁻³ A or 1.303 mA

From the current divider rule, I4 = I × (R4/(R3+R4)

That is the currrent flowing throuhgh R4 = 1.303 × (45/(45+55)) = 0.5865 mA

3 0

4 years ago

A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9

Black_prince [1.1K]

Answer: