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Whitepunk [10]
3 years ago
6

Which feature signifies to astronomers that a distant star is part of a planetary system

Physics
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0
Because it also can be apart of the milky way galaxy

liq [111]3 years ago
6 0

Answer: a) The star periodically dims.


A star is the body of gas in which nuclear fusion of gases like helium and hydrogen  takes place due to this reason the star glows or dim. Star gets the ability to generate light because of this nuclear fusion which  cannot be observed in planets although the process of generation of star and planet is the same.  In distantly located star under observation, it's luminosity ( the property of  emitting lighting) is controlled by size of the star, the larger the size of the star it will have greater surface area the more profound will be the nuclear fusion in it and more light will be emitted. Second factor is the gaseous interaction of gases in and around the star and their temperature which causes the change in the light which has to pass through a layer of these gases. Therefore,  the distant star observed will show light fluctuations.



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Natasha_Volkova [10]

Explanation:

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First, your definition of a shadow is incorrect. A shadow is an area that receives less light than its surroundings because a specific source of light is blocked by whatever is "casting" the shadow. Your example of being outside reveals this. The sky and everything around you in the environment (unless you are surrounded by pitch black buildings) is sending more than enough light into your shadow, to reveal the pen to your eyes. The sky itself diffuses the sunlight everywhere, and the clouds reflect plenty of light when they are not directly in front of the Sun.

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4 0
3 years ago
10. Find the mass density of a ball with 22.0 g and a radius of 0.875 cm.
Ede4ka [16]

Answer:

Mass (m) = 22.0 g

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First find ( volume) ;

v =  \frac{4}{3} \pi \:  {r}^{3}  \\  \\ v =  \frac{4}{3}  \times 3.14 \times ( {0.875)}^{3}  \\  \\ v =  \frac{4}{3}   \times 3.14 \times 0.66992187  \:  {cm}^{3} \\  \\ v = 2.8 \:  {cm}^{3}

Density =  \frac{mass}{volume}  \\  \\ d =  \frac{m}{v}  \\  \\ d =  \frac{22}{2.8}  \\  \\ d = 7.857 \:  \frac{g}{ {cm}^{3} }

I hope I helped you^_^

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dimulka [17.4K]
I would say that the answer is C
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