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garri49 [273]
3 years ago
6

What is the magnitude of a point charge that would create an electric field of 1.18 N/C at points 0.822 m away?

Physics
1 answer:
katrin [286]3 years ago
4 0

Answer:

q = 8.85 x 10⁻¹¹ C

Explanation:

given,

Electric field, E = 1.18 N/C

distance, r = 0.822 m

Charge magnitude = ?

using formula of electric field.

E = \dfrac{kq}{r^2}

k is the coulomb constant

q= \dfrac{Er^2}{k}

q= \dfrac{1.18\times 0.822^2}{9\times 10^9}

  q = 8.85 x 10⁻¹¹ C

The magnitude of charge is equal to q = 8.85 x 10⁻¹¹ C

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Answer;

The temperature change for the second pan will be lower compared to the temperature change of the first pan

Explanation;

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You are making a round trip from City A to City B and back to City A again at constant speed. At what point in the trip is your
MA_775_DIABLO [31]

Answer:

Halfway between B and A on the return leg.

Explanation:

Your average SPEED for the entire trip will equal your constant speed as the time and distance increase at proportionate rates.

Your average VELOCITY will equal your constant speed while you travel from A to B because time and displacement are increasing at proportionate rates.

When you turn around at B to return, your Displacement is now decreasing while your travel time continues to increase, so your average velocity decreases.

Lets say the distance from A to B is 90 km and your constant speed is 30 km/hr.

your average speed is 30 km/hr because you took 6 hrs to travel 180 km

We want to find your position when your average velocity is 30/3 = 10 km/hr

it took 3 hrs to go 90 km from A to B. Let t be the time lapsed since turn around

your displacement is given by d = 90 - 30(t)

and your total time of travel is t + 3 hrs

 v = d/t

10 = (90 - 30t) / (t + 3)

10(t + 3) = (90 - 30t)

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3 0
2 years ago
A 388 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s. What is the length of the
Marizza181 [45]

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2 years ago
A flywheel in a motor is spinning at 590 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75
Gnom [1K]

Answer:

Explanation:

Hello,

Let's get the data for this question before proceeding to solve the problems.

Mass of flywheel = 40kg

Speed of flywheel = 590rpm

Diameter = 75cm , radius = diameter/ 2 = 75 / 2 = 37.5cm.

Time = 30s = 0.5 min

During the power off, the flywheel made 230 complete revolutions.

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + ω₂) / 2] × 0.5

But ∇θ = 230 revolutions

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230 / 0.5 = (530 + ω₂) / 2

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a)

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α = (ω₂ - ω₁) / t

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α = -260 / 0.5

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b)

ω₂ = ω₁ + αt

0 = 590 +(-520)t

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solve for t

t = 590 / 520

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X seconds = 1.13min

x = (60 × 1.13) / 1

x = 68seconds

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∇θ = [(590 + 0) / 2] × 1.13

∇θ = 333.35 rev/min

8 0
3 years ago
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