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Zolol [24]
3 years ago
11

If the amplitude of a wave is doubled, it has half the velocity. TRUE or FALSE?

Physics
1 answer:
blondinia [14]3 years ago
7 0

Answer:

true

Explanation:

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Heat and/or energy are transferred from one object to another if the objects have _________ temperature(s).
NISA [10]

Answer:

.....different temperatures

Explanation:

heat is a form of energy that is transfered from a body of high temperature to a body of low temperature....Cannot happen if the two bodies have the same temperature(thermal equilibrium)

7 0
3 years ago
PLZ HELP!!!!!!! My favorite playground equipment is the swings. In 1-3 sentences explain a pattern of motion that u predict u'll
In-s [12.5K]

My favorite playground equipment is the swings.

4 0
3 years ago
What is refraction?
Damm [24]
B- light bends as it passes through an object ( a would be reflect)
4 0
3 years ago
KIIS FM broadcasts at 102.7 MHz, what is the wavelength of that radio wave?
marysya [2.9K]

Answer:

2.92 m

Explanation:

As we know, frequency × Wavelength = Speed of light

so here frequency of 102.7 MHz can be written as 102.7× 10⁶ Hz..

So Lambda (wavelength) = 3×10⁸/ 102.7 × 10⁶ which gives 2.92 metres or 2.92 × 10¹⁰ Å

3 0
3 years ago
A 5-g lead bullet traveling in 20°C air at 300 m/s strikes a flat steel plate and stops.
densk [106]

To solve this problem it is necessary to apply the concepts related to the Kinetic Energy and the Energy Produced by the heat loss. In mathematical terms kinetic energy can be described as:

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

Replacing we have that the Total Kinetic Energy is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (5*10^{-3})(300)^2

KE =  225J

On the other hand the required Energy to heat up t melting point is

Q_1 = mC_p \Delta T

Q_2 = L_f m

Where,

m = Mass

C_p =Specific Heat

\Delta T =Change at temperature

L_f = Latent heat of fussion

Heat required to heat up to melting point,

Q = Q_1+Q_2

Q = mC_p \Delta T+L_f m

Q = 5*0.128*(327-20) + 5*24.7

Q = 310J

The energy required to melt is larger than the kinetic energy. Therefore the heat of fusion of lead would be 327 ° C: The melting point of lead.

4 0
3 years ago
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