Answer:
a.) Maximum height of the projectile. =32.5m
b.) The time it takes to reach the maximum height=2.6s
c.) Time of flight=2.6s
d.) Range=99.5m
Explanation:
The acceleration of the race car is 6 m/s²
The given parameters;
initial velocity of the race car, u = 6 m/s
final velocity of the race car, v = 36 m/s
time of motion, t = 5 s
Acceleration is defined as the change in velocity per change in time of motion.
The acceleration of the race car is calculated as follows;

Thus, the acceleration of the race car is 6 m/s²
Learn more here: brainly.com/question/17280180
Answer:
0.57 m
Explanation:
First of all, we need to calculate the time it takes for the ball to cover the horizontal distance between the starting position and the crossbar. This can be done by analzying the horizontal motion only. In fact, the horizontal velocity is constant and it is

And the distance to cover is
d = 19 m
So the time taken is

Now we want to find how high the ball is at that time. The initial vertical velocity is

So the vertical position of the ball at time t is

where g = 9.8 m/s^2 is the acceleration of gravity. Substituting t = 2.04 s, we find

The crossbar height is 3.05 m, so the difference is

So the ball passes 0.57 m above the crossbar.
Answer:
cation, anion
Explanation:
Binary Ionic Compounds- Binary means 2, ionic relates to charges. Therefore binary ionic compounds have TWO elements, with charges that cancel eachother out. The cation (or positive charge) goes before the anion (or negative charge)
example:
NaCl
Na^+1
Cl^-1
Sodium Chloride
Answer:
6.5 m above the floor and 5 m above Christine's hand when it reaches the maximum height.
Explanation:
Let g = 10 m/s2 be the gravitational deceleration that affects the ball vertical motion so it comes to the maximum height at 0 speed. We can use the following equation of motion to find out the distance traveled by the ball from where it's thrown:

where v = 0 m/s is the final velocity of the ball when it reaches maximum level,
= 10m/s is the initial velocity of the ball when it starts, g = -10 m/s2 is the deceleration, and
is the distance traveled, which we care looking for:


So the ball is 5 m above Christine' hands when it reaches maximum height, and since the hand is 1.5 m above the floor, the ball is 5 + 1.5 = 6.5 m above the floor when it reaches maximum height.