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dangina [55]
3 years ago
10

A sound-producing object is moving away from an observer. The sound the observer hears will have a frequency that actually being

produced by the object.
the same as

higher than

lower than

need ASAP!!!
Physics
2 answers:
kozerog [31]3 years ago
6 0
Lower than, this is due to the doplar effect
padilas [110]3 years ago
5 0

Answer:

Lower than

Explanation:

According to Doppler’s effect, the observer will not hear the same frequency of sound if there is relative motion between the source and observer. When source is moving away from the observer the frequency perceived by the observer will be less than actual frequency as given by the following formula:

                                   f1 = (V/V+Vs)*f  

where,

f1 = frequency heard by the observer  

f = actual frequency  

V = velocity of sounds waves  

Vs = velocity of source

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svetlana [45]
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6 0
3 years ago
Read 2 more answers
The frequency of a wave is 200 Hz. The wavelength is 0.1 m. What is the period of the wave?
Aleks04 [339]
The formula for the period of wave is: wave period is equals to 1 over the frequency.waveperiod=\frac{1}{frequency}
To get the value of period of wave you need to divide 1 by 200 Hz. However, beforehand, you have to convert 200 Hz to cycles per second. So that would be, 200 cyles per second or 200/s.
By then, you can start the computation by dividing 1 by 200/s. Since 200/s is in fractional form, you have to find its reciprocal form and multiply it to one which would give you 1 (one) second over 200. This would then lead us to the value 0.005 seconds as the wave period.

wave period= 1/200 Hz
Convert Hz to cycles per second first
200 Hz x 1/s= 200/second
Make 200/second as your divisor, so:

wave period= 1/ 200/s

get the reciprocal form of 200/s which is s/200

then you can start the actual computation:

wave period= 1 x s divided by 200

this would give us an answer of 0.005 s. 
6 0
3 years ago
What happens to the wavelength of a wave if you increase the frequency?
dezoksy [38]

The product of (wavelength) times (frequency) is always the same number ...
the speed of the wave in whatever material it's traveling through.  So if the
frequency is increased, then the wavelength must <em><u>de</u></em>crease by the same
factor, in order to keep the product the same.


4 0
3 years ago
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