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4 years ago

Write in verbal expression. m-14=44?

Mathematics

2 answers:

Alborosie4 years ago

8 0

A number m minus 14 equals 44

liubo4ka [24]4 years ago

6 0

A number less than fourteen is equal to forty-four

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The Ramirez family has a circular garden with a diameter of 22 ft. They cover the garden with mulch. The cost of mulch is $1.25

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It will cost $475 to cover the garden

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3 years ago

HELP ASAP PLEASE AND SHOW WORK!!! Write the vertex form of the following equation. y= x^2+6x-5

valkas [14]

Answer:

<h3> $\boxed{\bold{y=(x+3)^2-14}}$ </h3>

Step-by-step explanation:

y= x²+6x-5

completing the square: a²+2ab+b² = (a+b)² where a²=x² (so a=x) and 2ab=6x (so b would be 3):

$y=x^2+6x-5\\\\y=\underline{x^2+2\cdot x\cdot3+3^2}-3^2-5\\\\y=(x+3)^2-9-5\\\\\underline{y=(x+3)^2-14}\\\\\\vertex:\ \ (-3,\,-14)$

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3 years ago

1. (2 points) The starship Enterprise just picked up a strange creature called a tribble.

koban [17]

Answer:

21 tribbles on the 7th night

Step-by-step explanation:

every night 3 tribbles appear meaning that the tribbles spawn rate is y=3x

y= number of tribbles

x= number of nights

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3 years ago

The sum of three numbers is 30. The middle number is 5 less than the biggest number, while the smallest number is one-third of t

Semmy [17]

15, 10, 5

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3 years ago

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the

Rasek [7]

Answer:

$\mu_{p} = p = 0.06$

And the standard error is given by:

$SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123$

And we want to find this probability:

$P(\hat p < 0.03)$

We can calculate the z score for this case and we got:

$z = \frac{\hat p -\mu_p}{\Se_p} = \frac{0.03-0.06}{0.0123}= -2.440$

And using the normal distribution table or excel we got:

$P(\hat p < 0.03)= P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

For this case we can find the mean and standard error for the sample proportion with these formulas:

$\mu_{p} = p = 0.06$

And the standard error is given by:

$SE_{p} = \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$SE_[p]= \sqrt{\frac{0.06*(1-0.06)}{373}}= 0.0123$

And we want to find this probability:

$P(\hat p < 0.03)$

We can calculate the z score for this case and we got:

$z = \frac{\hat p -\mu_p}{\SE_p} = \frac{0.03-0.06}{0.0123}= -2.440$

And using the normal distribution table or excel we got:

$P(\hat p < 0.03)= P(Z$

8 0

4 years ago