The recoil velocity will be 5.42 m/s.
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How is Newton 3rd law stated ?</h3>
Newton 3rd law state that in every action, there will be equal and opposite reaction.
Given that a rifle bullet of mass 60.0 g leaves the muzzle of a rifle with a velocity of 2.8 x 10² m/s. If the rifle has a mass of 3.1 kg, with what velocity will it recoil ?
The parameter given are;
- mass of the bullet m = 60g = 0.06Kg
- Velocity of the bullet u = 2.8 x 10² m/s
- mass of the rifle M = 3.1 kg
mu = Mv
Substitute all the parameters
0.06 × 2.8 × 10² = 3.1 v
16.8 = 3.1v
Make v the subject of formula
v = 16.8/3.1
v = 5.42 m/s
Therefore, the recoil velocity will be 5.42 m/s.
Learn more about Recoil Velocity here: brainly.com/question/15435914
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Answer:
0.2625 N/C
Explanation:
Force of attraction =
where Q₁ and Q₂ are charges and R is distance between charges.K is a constant equal to 9 x 10⁹.
=
= 0.2625 N/C
A=(Vo-V)/t=(10-0)/0.26=10/0.26=38.46m/s2
F=ma=70*38.46=2692.3N
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