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White raven [17]
2 years ago
7

A. In the building there are 133 steps from the ground floor to the sixth floor.

Physics
1 answer:
faust18 [17]2 years ago
7 0

(a) The work done by the person is 18.83465 kJ.

(b) The average power performed by the person during the walk is 51.4 W.

(c) The amount of food calories burnt is 4.5 Cal.

<h3>Work done by the person</h3>

The work done by the person is calculated as follows;

W = Fd

W = mgh

W = (89.2 x 9.8) x (0.162 x 133)

W = 18,834.65 J

W = 18.83465 kJ

<h3>Average power of the person</h3>

P = Fv

where;

  • v is velocity

v = (d)/t

v = (133 x 0.162)/(6 x 60   +  6)

v = (133 x 0.162)/(366)

v = 0.0588 m/s

P = (89.2 x 9.8) x 0.0588

P = 51.4 W

<h3>Amount of food calories burnt</h3>

4.1868 kJ = 1 Cal

18.83465 kJ = ?

= 4.5 Cal

Learn more about work done here: brainly.com/question/8119756

#SPJ1

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Answer:

a1 = 3.56 m/s²

Explanation:

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Radius of pulley; r = D/2 = 0.15/2 = 0.075 m

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Time; t = 0.75

I've drawn a free body diagram to depict this question.

Since we want to find the tension of the cord on 3.00 kg book, it means we are looking for T1 as depicted in the FBD attached. T1 is calculated from taking moments about the x-axis to give;

ΣF_x = T1 = m1 × a1

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s = ut + ½at²

our s is now Δx and a1 is a.

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u is initial velocity and equal to zero because the 3 kg book was at rest initially.

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3 years ago
Calculate the pressure the fluid exerted on your diver. The acceleration of gravity is 9.8 m/s2 and the density of the water is
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Complete question:

A diver is 10 m below the surface of water. Calculate the pressure the fluid exerted on the diver. The acceleration of gravity is 9.8 m/s2 and the density of the water is 1000 kg/m3. Answer in units of Pa. Show your work.

Answer:

Tthe pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa

Explanation:

Given;

density of water, ρ = 1000 kg/m³

diver's position below the surface of the water, h = 10 m

acceleration due to gravity, g = 9.8 m/s²

Let the atmospheric pressure, P₀ = 101325 Pa

The pressure 10 m below the surface of the water is calculated as;

P =  P₀  + ρgh

P = 101325 Pa  +  (1000 x 9.8 x 10)Pa

P = 199325 Pa

P = 1.99 x 10⁵ Pa.

Therefore, the pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa

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Answer:

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Answer:

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