Answer:
C because it is in earth's mantle
<span>PE = mass * height * g = 87.60 J
Frictional force = m * g * sin theta * uk = 4.7 kg * 9.81 m/sec^2 * sin 36.87 * 0.3 = 8.299 N
Work done by friction = force * distance = 41.50 J
Remaining energy to be converted to KE = 87.60 J - 41.50 J = 41.10 J</span>hope it helps
1. Displacement = 50 m North. Distance = 150m
Displacement is a vector. Distance is a scalar.
2. Displacement is 100 miles East.
Answer:
Question doesn't make sense
Answer:
70 °C
Explanation:
Note : 1 GPA = 1000MPa ; 1 μ = 10⁻⁶
Strain (∈) = δl / l = ∝ ΔT
Elastic modulus = Direct stress (strength)/Strain
20 * 10³ = 10 / ∝ ΔT
ΔT = 10 / 20 * 10³ ∝
= 10 / ( 20 * 10³ *10⁻⁶)
= 10/0.02 = 50
= 50 °C
Therefore Temperature for concrete crack = ambient temperature + ΔT
20°C + 50 °C
= 70 °C