To solve this problem we will apply the concepts of energy conservation and Newton's second law that defines force as the product of the object's mass with its acceleration. Additionally we will apply concepts related to the kinematics equations of linear motion.
For conservation of energy we have that work is equal to kinetic energy therefore,


Here,
F = Force
d = Displacement
m = Mass
v= Velocity
At the same time we have the relation of

Therefore the value of the force can be interpreted as the rate of increase in energy per unit of distance, which makes it equivalent to

Applying Newton's Second Law



In 4 seconds final velocity of the object becomes



Then the work done is equal to,




Then the displacement is,




Therefore the distance moved is 16m
Answer:
Explanation:
We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .
f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .
f will be lowest when v₀ is highest .
velocity of observer is highest when he is at the equilibrium position or at middle point .
So apparent frequency is lowest when observer is at the middle point and going away from the source while swinging to and from before the source of sound .
Answer
given,
mass of satellite = 2400 Kg
speed of the satellite = 6.67 x 10³ m/s
acceleration of satellite = ?
gravitational force of the satellite will be equal to the centripetal force


Assuming the radius of circular orbit = 8.92 x 10⁶ m
now,

F = 11970.11 N
acceleration,


a = 4.98 m/s²
Answer:
206 pm
Explanation:
We are given that
Potential difference,
Distance,d=
We have to determine the de Brogile wavelength of the electron.
A=11 and B=5


Charge on electron,q =
Mass of electron=m=
Speed of electron,
Using the formula

v=
de Brogile wavelength, 
Where 

1 pm=

Answer:
Let the power delivered by the sound wave be 'P'
Intensity by definition is the power delivered per unit area.
i.e. I =
dA
dP
;
In spherical polar coordinate system dA = r
2
Ω
I =
r
2
Ω
dP
;
I ∝
r
2
1
So if distance increases 3 fold. The Intensity becomes
9
1
times the initial