Answer:
The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.
Explanation:
The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:
n = 1.375x10⁻⁵ mol
The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):
1.375x10⁻⁵ mol _________ 19.9 units
x _________ 25.2 units
x = 1.741x10⁻⁵mol
Finally, we can calculate the Cu²⁺ concentration :
C = 1.741x10⁻⁵mol / 0.025 L
C = 6.964x10⁻⁴ M
The continuous cycling of carbon in the earyh is known as the carbon cycle.
<h3>What is the carbon cycle?</h3>
The carbon cycle is a cycle which explains the various processes by which carbon is recycled between the atmosphere and the earth.
The constant flow of carbon on earth through organisms and the air is known as the carbon cycle. Plants absorb carbon from the atmosphere in the form of carbon dioxide. They use it for respiration and food production.
Animals consume plants, transferring carbon along the food chain.
Plants and animals respire and release carbon into air. When the animals and plants die, they are eaten by decomposers.
Carbon enters back into the atmosphere in the form of carbondio dioxide.
Therefore, the continuous cycling of carbon in the earth is known as the carbon cycle.
Learn more about carbon cycle at: brainly.com/question/25845923
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No, They need something to hold on to, such as dirt
The first thing you need to do is convert mL into L
so (175 mL)(.001L/1mL)=.175L then you multiply by the Molarity of H3PO4 which is 3.5mol/L so (.175L)(3.5mol/L)=.6125 mol H3PO4, and since it wants the answer in grams you then multiply (.6125molH3PO4) by the molar mass of H3P04 which is about 97.99g and your answer is 60.02g which is about 60 grams of H3PO4. Hope this helped
<u>Answer:</u> The spacecraft traveled 345 km during the given time.
<u>Explanation:</u>
To calculate the distance of spacecraft, we use the equation:
We are given:
Velocity = 2.3 km/sec
Time = 2.5 mins = 150 sec (Conversion factor: 1 min = 60 sec)
Putting values in above equation, we get:
Hence, the spacecraft traveled 345 km during the given time.
