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swat32
2 years ago
6

Select the correct answer from each drop-down menu. carbon is found in all living organisms. the constant flow of carbon on eart

h through organisms and the air is known as the carbon cycle. absorb carbon from the atmosphere in the form of carbon dioxide. they use it for respiration and . animals consume plants, transferring carbon along the food chain. plants and animals respire and release carbon into air. when the animals and plants die, they are eaten by . carbon enters back into the atmosphere in the form of .
Chemistry
1 answer:
Nady [450]2 years ago
5 0

The continuous cycling of carbon in the earyh is known as the carbon cycle.

<h3>What is the carbon cycle?</h3>

The carbon cycle is a cycle which explains the various processes by which carbon is recycled between the atmosphere and the earth.

The constant flow of carbon on earth through organisms and the air is known as the carbon cycle. Plants absorb carbon from the atmosphere in the form of carbon dioxide. They use it for respiration and food production.

Animals consume plants, transferring carbon along the food chain.

Plants and animals respire and release carbon into air. When the animals and plants die, they are eaten by decomposers.

Carbon enters back into the atmosphere in the form of carbondio dioxide.

Therefore, the continuous cycling of carbon in the earth is known as the carbon cycle.

Learn more about carbon cycle at: brainly.com/question/25845923

#SPJ4

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Copper has a specific heat of 0.385 J/gºC.
Anna71 [15]

Answer:

The final temperature is 348.024°C.

Explanation:

Given data:

Specific heat of copper = 0.385 j/g.°C

Energy absorbed = 7.67 Kj (7.67×1000 = 7670 j)

Mass of copper = 62.0 g

Initial temperature T1 = 26.7°C

Final temperature T2 = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Q = m.c. ΔT

7670 J = 62.0 g × 0.385  j/g °C ×( T2- 26.7 °C )

7670 J = 23.87 j.°C ×( T2- 26.7 °C )

7670 J / 23.87 j/°C = T2- 26.7 °C

T2- 26.7 °C = 321.324°C

T2 = 321.324°C + 26.7 °C

T2 = 348.024°C

The final temperature is 348.024°C.

6 0
4 years ago
How many milligrams of MgI2 must be added to 257.7 mL of 0.087 M KI to produce a solution with [I−] = 0.1000 M?
lbvjy [14]

Answer:

The answer is 465.6 mg of MgI₂ to be added.

Explanation:

We find the mole of ion I⁻ in the final solution

C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol

But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.

So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.

Hence, the weight of MgI₂ must be added is

Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg

4 0
3 years ago
KCI is a molecule. True or False
Monica [59]

Answer: duh

Explanation:

4 0
3 years ago
Read 2 more answers
Mean, median and mode are best described as which?
Nonamiya [84]

Answer:

B. Measures of central tendency

Explanation:

Mean, median and mode are best described as measures of central tendency of a given data set.

Mean is the average of the samples given

Mode is the data point with the most frequent occurrence

Median is the data point that lies in the middle

  • All these parameters tells us how far a data point is from the middle or how close they are.
5 0
3 years ago
A chemist makes 940. mL of sodium carbonate (Na_2CO_3) working solution by adding distilled water to 200. mL of a 0.171 m stock
Alexxandr [17]

Answer:

The answer is 0.0698 M

Explanation:

The concentration was prepared by a serial dilution method.

The formula for the preparation I M1V1 = M2V2

M1= the concentration of the stock solution = 0.171 M

V1= volume of the stock solution taken = 200 mL

M2 = the concentration produced

V2 = the volume of the solution produced = 940 mL

Substitute these values in the formula

0.171 × 200 = 490 × M2

34.2 = 490 × M2

Make M2 the subject of the formula

M2 = 34.2/490

M2 = 0.069795

M2 = 0.0698 M ( 3 s.f)

The concentration of the Chemist's working solution to 3 significant figures is 0.0698M

6 0
3 years ago
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