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iris [78.8K]
3 years ago
7

Two electrons are separated by a distance of 3.00 x 10^-6 meter. What are the magnitude and direction of the electrostatic force

s each exerts on the other?
Physics
1 answer:
Brilliant_brown [7]3 years ago
5 0
The electrostatic force between two charges q1 and q2 is given by
F=k_e  \frac{q_1 q_2}{r^2}
where 
k_e = 8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant
r=3.00 \cdot 10^{-6} m is the distance between the two charges.

In our problem, the two charges are two electrons, so their charges are equal and equal to 
q_1=q_2=q=-1.6 \cdot 10^{-19}C

By substituting these values, we find the intensity of the force between the two electrons:
F=(8.99 \cdot 10^9 N m^2 C^{-2})  \frac{(-1.6 \cdot 10^{-19}C)(-1.6 \cdot 10^{-19}C)}{(3.00 \cdot 10^{-6} m)^2}=2.6 \cdot 10^{-17}N

This is the magnitude of the force each electron exerts to the other one. The direction is given by the sign of the charges: since the two electrons have same charge, they repel each other, so the force exerted by electron 1 is toward electron 2 and viceversa.
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Answer:

at the speed of light (c=3.0\cdot 10^8 m/s)

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An electric iron connected to a 110 V source draws 9 A of current. How much heat (in joules) does it generate in a minute?
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<h3>How to determine the linear expansion</h3>

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Using the formula:

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Substitute into the formula

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Therefore, the steel would expand by 4. 8 * 10^-3 cm

Learn more about linear expansion here:

brainly.com/question/14325928

#SPJ1

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