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Brilliant_brown [7]
3 years ago
13

At a constant pressure, melting occurs by A) producing energy. B) absorbing energy. C) releasing energy. D) circulating energy.

Physics
2 answers:
olganol [36]3 years ago
5 0
Realizing energy.......
Mamont248 [21]3 years ago
4 0

The correct answer to the question is B) Absorbing energy.

EXPLANATION:

As per our question, the substance is melting at constant pressure.

Melting is a process of phase change in which a solid substance is converted into liquid at its melting point. For instance, melting of ice.

The thermal energy of the liquid is more as compared to solid. Hence, the solid must have to absorb energy to be converted into liquid. The absorbed energy will be utilized in changing the solid into its corresponding liquid.

As melting is a process of phase change or state change, the temperature of the substance will be constant as long as total solid is not converted into liquid. Hence, the kinetic energy of the substance will be constant. So, the energy absorbed during melting will only change the configuration of the substance i.e the absorbed energy is converted into potential energy of the system.

Hence, the correct answer of the question is that energy is absorbed during melting.

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You are on a cruise ship traveling north at a speed of 13 m/s with respect to land. 1) if you walk north toward the front of the
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In order to find the our own velocity with respect to land,we need to apply the theory of relative velocity.


Now consider the velocity of the ship traveling towards the north with respect to land as A.Consider our own velocity headed northwards as B.

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A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.6 m/s . Two seconds later t
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Answer:

A) t = 7.0 s    

B) x = 25 m  

C) v = 10 m/s

Explanation:

The equations for the position and velocity of an object traveling in a straight line is given by the following expressions:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

A)When both friends meet, their position is the same:

x bicyclist = x friend

x0 + v0 · t + 1/2 · a · t² = x0 + v · t

If we place the center of the frame of reference at the point when the bicyclist starts following his friend, the initial position of the bicyclist will be 0, and the initial position of the friend will be his position after 2 s:

Position of the friend after 2 s:

x = v · t

x = 3.6 m/s · 2 s = 7.2 m

Then:

1/2 · a · t² = x0 + v · t       v0 of the bicyclist is 0 because he starts from rest.

1/2 · 2.0 m/s² · t² = 7.2 m + 3.6 m/s · t

1  m/s² · t² - 3.6 m/s · t - 7.2 m = 0

Solving the quadratic equation:

t = 5.0 s

It takes the bicyclist (5.0 s + 2.0 s) 7.0 s to catch his friend after he passes him.

B) Using the equation for the position, we can calculate the traveled distance. We can use the equation for the position of the friend, who traveled over 7.0 s.

x = v · t

x = 3.6 m/s · 7.0 s = 25 m

(we would have obtained the same result if we would have used the equation for the position of the bicyclist)

C) Using the equation of velocity:

v = a · t

v = 2.0 m/s² · 5.0 s = 10 m/s

8 0
3 years ago
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