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3 years ago

At a constant pressure, melting occurs by A) producing energy. B) absorbing energy. C) releasing energy. D) circulating energy.

Physics

2 answers:

olganol [36]3 years ago

5 0

Realizing energy.......

Mamont248 [21]3 years ago

4 0

The correct answer to the question is B) Absorbing energy.

EXPLANATION:

As per our question, the substance is melting at constant pressure.

Melting is a process of phase change in which a solid substance is converted into liquid at its melting point. For instance, melting of ice.

The thermal energy of the liquid is more as compared to solid. Hence, the solid must have to absorb energy to be converted into liquid. The absorbed energy will be utilized in changing the solid into its corresponding liquid.

As melting is a process of phase change or state change, the temperature of the substance will be constant as long as total solid is not converted into liquid. Hence, the kinetic energy of the substance will be constant. So, the energy absorbed during melting will only change the configuration of the substance i.e the absorbed energy is converted into potential energy of the system.

Hence, the correct answer of the question is that energy is absorbed during melting.

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Choose the correct statement regarding the behavior of water. a. The water phase with the highest heat capacity is gas vapor. b.

e-lub [12.9K]

Answer:

D. The ice-to-liquid phase change of water requires less energy than the liquid-to-vapor phase.

Explanation:

In the phase change from liquid to gas, the bonds between atoms are completely broken. The phase change from liquid to gas requires more energy because the bonds must be completely broken for it to take place, rather than just loosened as in the phase change of solid to liquid.

Phase changes can have a strong stabilizing effect on temperatures that are not near the melting and boiling points, since evaporation and condensation occur even at temperatures below the boiling point.

More energy is required to evaporate water below the boiling point than at the boiling point, because the kinetic energy of water molecules at temperatures below 100°C is less than that at 100°C, so less energy is available from random thermal motions.

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3 years ago

Which part of the eye is used to see things in high detail?

irina1246 [14]

Answer:

Retina is the part of eye which is used to see things in high details

7 0

3 years ago

Air friction damps a tuning fork so the amplitude decreases by 1/10 per second. Resonances] 10 Hz. what % chnge in frequency res

aleksandr82 [10.1K]

Answer:

The percentage change in frequency is 10%.

Explanation:

Given that,

Amplitude decreases by 1/10 per second.

Resonance = 10 Hz

We need to calculate the change in frequency

Using formula of change in frequency

$\Delta f=\Delta A\times R$

Put the value into the formula

$\Delta f=\dfrac{1}{10}\times10$

$\Delta f=1\ Hz$

We need to calculate the resonant frequency

Using formula of resonant frequency

$f_{r}=R-\Delta f$

Put the value into the formula

$f_{r}=10-1$

$f_{r}=9\ Hz$

We need to calculate the percentage change in frequency

Using formula of percentage change in frequency

$f=\dfrac{10-9}{10}$

$f=10\%$

Hence, The percentage change in frequency is 10%.

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4 years ago

The magnitude of the electric current is directly proportional to the _____________ of the electric field.

Harlamova29_29 [7]

The magnitude of the electric current is directly proportional to the "Electric Charge" <span>of the electric field.

Hope this helps!</span>

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3 years ago

Two 2 kg masses is placed at either end of a rod that has a mass of .5 kg and a length of 3 m. What is the moment of inertia if

sergij07 [2.7K]

Explanation:

a) $I=\displaystyle \sum_{i}m_ir_i^2$

where $r_i$ is the distance of the mass $m_i$ from the axis of rotation. When the axis of rotation is placed at the end of the rod, the moment of inertia is due only to one mass. Therefore,

$I= mr^2 = (2\:kg)(3\:m)^2 = 18\:kg-m^2$

b) When the axis of rotation is placed on the center of the rod, the moment is due to both masses and the radius r is 1.5 m. Therefore,

$\displaystyle I= \sum_{i}m_ir_i^2 = 2(2\:kg)(1.5\:m)^2 = 9\:kg-m^2$

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3 years ago