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3 years ago

GUESS WHAT??? i'LL MAKE YOU BRAINLIEST! PLEASE HURRY!

Physics

2 answers:

nadya68 [22]3 years ago

6 0

Answer:

B) day and night

Explanation:

Think about what Earth's rotation looks like.

Here is proof that my answer is correct:

IRISSAK [1]3 years ago

5 0

rotation of Earth causes day and night . thank you

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Suppose you take a 50gram ice cube from the freezer at an initial temperature of -20°C. How much energy would it take to complet

notsponge [240]

Answer:

The amount of energy required is $152.68\times 10^{3}Joules$

Explanation:

The energy required to convert the ice to steam is the sum of:

1) Energy required to raise the temperature of the ice from -20 to 0 degree Celsius.

2) Latent heat required to convert the ice into water.

3) Energy required to raise the temperature of water from 0 degrees to 100 degrees

4) Latent heat required to convert the water at 100 degrees to steam.

The amount of energy required in each process is as under

1) $Q_1=mass\times S.heat_{ice}\times \Delta T\\\\Q_1=50\times 2.05\times 20=2050Joules$

where

$'S.heat_{ice}$ ' is specific heat of ice = $2.05J/^{o}C\cdot gm$

2) Amount of heat required in phase 2 equals

$Q_2=L.heat\times mass\\\\\therefore Q_{2}=334\times 50=16700Joules$

3) The amount of heat required to raise the temperature of water from 0 to 100 degrees centigrade equals

$Q_3=mass\times S.heat\times \Delta T\\\\Q_1=50\times 4.186\times 100=20930Joules$

where

$'S.heat_{water}$ ' is specific heat of water= $4.186J/^{o}C\cdot gm$

4) Amount of heat required in phase 4 equals

$Q_4=L.heat\times mass\\\\\therefore Q_{4}=2260\times 50=113000Joules\\\\$ $\\\\\\\\$ Thus the total heat required equals $Q=Q_{1}+Q_{2}+Q_{3}+Q_{4}\\\\Q=152.68\times 10^{3}Joules$

5 0

3 years ago

a motorcycle traveling on the highway at a velocity of 120 kilometre-per-hour passes a car traveling at a velocity of 90 kilomet

musickatia [10]

Answer:

The relative velocity of the motorcycle to a passenger in the car is 30 km/h

Explanation:

The question relates to the principle of relative velocity and reference frames

The given parameters are;

The velocity of the motorcycle, v₁ = 120 km/h

The velocity of the car, v₂ = 90 km/h

The relative velocity of an object X with regards to another object Y is the velocity the object X will seem to be moving with to an observer in the rest frame of object Y written as $\underset{v}{\rightarrow}_{X|Y}$ = $\underset{v}{\rightarrow}_{X}$ - $\underset{v}{\rightarrow}_{Y}$