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4 years ago

A car stops with an acceleration of -20 m/s/s in 8 seconds. How far did it go while stopping?

Physics

1 answer:

Sophie [7]4 years ago

3 0

Answer:

640 m.

Explanation:

The following data were obtained from the question:

Acceleration (a) = –20 m/s/s

Time (t) = 8 s

Final velocity (v) = 0 m/s

Distance (s) =.?

Next, we shall determine the initial velocity (u) of the car. This can be obtained as follow:

Acceleration (a) = –20 m/s/s

Time (t) = 8 s

Final velocity (v) = 0 m/s

Initial velocity (u)

a = (v – u) / t

–20 = (0 – u) / 8

–20 = – u / 8

Cross multiply

–20 × 8 = – u

– 160 = – u

Divide both side by – 1

u = – 160 / – 1

u = 160 m/s

Finally, we shall determine the distance travelled by the car before stopping as follow:

Time (t) = 8 s

Final velocity (v) = 0 m/s

Initial velocity (u) = 160 m/s

Distance (s) =.?

s = (v + u)t /2

s = (0 + 160) × 8 /2

s = (160 × 8) /2

s = 1280 / 2

s = 640 m

Therefore, the car travelled 640 m before stopping.

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fgiga [73]

Answer:

2354.4 Pa

40221 Pa

Explanation:

$\rho$ = Density = 1000 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth

The pressure difference would be

$\Delta P=\rho gh\\\Rightarrow \Delta P=1000\times 0.24\times 9.81\\\Rightarrow \Delta P=2354.4\ Pa$

The pressure difference in the first case is 2354.4 Pa

$\Delta P=\rho gh\\\Rightarrow \Delta P=1000\times 4.1\times 9.81\\\Rightarrow \Delta P=40221\ Pa$

The pressure difference in the second case is 40221 Pa

7 0

3 years ago

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LuckyWell [14K]

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3 years ago

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A wedge with an inclination of angle θ rests next to a wall. A block of mass m is sliding down the plane. There is no friction b

Softa [21]

Answer:

The net force on the block F(net) = mgsinθ).

Fw =mg(cosθ)(sinθ)

Explanation:

(a)

Here, m is the mass of the block, n is the normal force, \thetaθ is the wedge angle, and Fw is the force exerted by the wall on the wedge.

Since the block sliding down, the net force on the block is along the plane of the wedge that is equal to horizontal component of weight of the block.

F(net) = mgsinθ

The net force on the block F(net) = mgsinθ).

The direction of motion of the block is along the direction of net force acting on the block. Since there is no frictional force between the wedge and block, the only force acting on the block along the direction of motion is mgsinθ.

(b)

From the free body diagram, the normal force n is equal to mgcosθ .

n=mgcosθ

The horizontal component of normal force on the block is equal to force

Fw=n*sin(θ) that exerted by the wall on the wedge.

Substitute mgcosθ for n in the above equation;

Fw =mg(cosθ)(sinθ)

Since, there is no friction between the wedge and the wall, there is component force acting on the wall to restrict the motion of the wedge on the surface and that force is arises from the horizontal component for normal force on the block.

6 0

3 years ago

A free-falling golf ball strikes the ground and exerts a force on it

ozzi

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4 years ago

Suppose that instead of being inclined to Earth's orbit around the Sun, the Moonâs orbit was in the same plane as Earthâs orbit

ycow [4]

Answer:

c) 12

Explanation:

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If the Moon's orbit was in the same plane as that of the Earth's orbit. Every new Moon, there would be a Solar Eclipse. The Lunar cycle is of 29.5 Days which means there will be one new Moon every month. So there will be 12 Solar Eclipses every year.

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3 years ago