The loudness of a sound wave is most closely related to

Learning Goal: How do 2 ordinary waves build up a "standing" wave? A very generic formula for a traveling wave is: y1(x,t)=Asin(

zheka24 [161]

Answer:

Explanation:

=Asin(kx−ωt). This general mathematical form can represent the displacement of a string, or the strength of an electric field, or the height of the surface of water, or a large number of other physical waves!

Part C Find ye(x) and yt(t). Remember that yt(t) must be a trig function of unit amplitude. Express your answers in terms of A, k, x, ω, and t. Separate the two functions with a comma. Use parentheses around the argument of any trig functions.

Part E At the position x=0, what is the displacement of the string (assuming that the standing wave ys(x,t) is present)? Part G From

Part F we know that the string is perfectly straight at time t=π2ω. Which of the following statements does the string's being straight imply about the energy stored in the strJHJMNMMUJJHTGGHing?

a.There is no energy stored in the string: The string will remain straight for all subsequent times.

b.Energy will flow into the string, causing the standing wave to form at a later time.

c.Although the string is straight at time t=π2ω, parts of the string have nonzero velocity. Therefore, there is energy stored in the string.

d.The total mechanical energy in the string oscillates but is constant if averaged over a complete cycle.

3 0

3 years ago

An offshore oil well is 2 kilometers off the coast. The refinery is 4 kilometers down the coast. Laying pipe in the ocean is twi

shusha [124]

Answer:

Rectangular path

Solution:

As per the question:

Length, a = 4 km

Height, h = 2 km

In order to minimize the cost let us denote the side of the square bottom be 'a'

Thus the area of the bottom of the square, A = $a^{2}$

Let the height of the bin be 'h'

Therefore the total area, $A_{t} = 4ah$

The cost is:

C = 2sh

Volume of the box, V = $a^{2}h = 4^{2}\times 2 = 128$ (1)

Total cost, $C_{t} = 2a^{2} + 2ah$ (2)

From eqn (1):

$h = \frac{128}{a^{2}}$

Using the above value in eqn (1):

$C(a) = 2a^{2} + 2a\frac{128}{a^{2}} = 2a^{2} + \frac{256}{a}$

$C(a) = 2a^{2} + \frac{256}{a}$

Differentiating the above eqn w.r.t 'a':

$C'(a) = 4a - \frac{256}{a^{2}} = \frac{4a^{3} - 256}{a^{2}}$

For the required solution equating the above eqn to zero:

$\frac{4a^{3} - 256}{a^{2}} = 0$

a = 4

Also

$h = \frac{128}{4^{2}} = 8$

The path in order to minimize the cost must be a rectangle.

8 0

4 years ago

There is little sunlight at high latitudes during the winter, so few crops can grow even if temperatures are regulated. To addre

Kruka [31]

Answer;

the colors of light that plants require for photosynthesis

Explanation;

The color of light used for photosynthesis depends on the pigment in the plant. For example, green plants with chlorophylls and carotenoids have a maximum activity with violet-blue and red light.

White light contains various colors, including red, orange, yellow, green, blue, indigo and violet. When plants harvest light for photosynthesis, they only absorb a few colors and reflect the rest. Plants appear green because chlorophyll absorbs other colors and reflects green.

7 0

3 years ago

Read 2 more answers

the young’s modulus of aluminum is 69gpa, of nylon is 3gpa, of tungsten is 400gpa, and of copper is 117gpa. if equal-size sample

olga_2 [115]

Answer:

Least to most elongated: tungsten, copper, aluminum, nylon.

Explanation:

Materials with high Young's modulus are difficult to stretch. σ = Yε and ε = ΔL/L so an object with a high Young's modulus (Y) subject to a certain tensile stress (σ) will have a smaller strain than an object with a smaller Young's 's modulus subject to the same tensile stress. If strain (ε) is smaller, then ΔL will also be smaller.

3 0

2 years ago

14*3(36/2(1*3)/6<br><img src="https://tex.z-dn.net/?f=14%20%5Ctimes%203%2836%20%5Cdiv%202%281%20%5Ctimes%203%29%20%5Cdiv%206" id

GarryVolchara [31]

<h2>10.5</h2><h3>remember pemdas</h3>

parentheses
exponents <em>excluded for this problem</em>
multiplication
division
addition
subtraction

<h3>step 1. start with what is at the top of the list.</h3>

parentheses

<h3>step 2. do 1 times 3 since it comes before division, and is in parentheses.</h3>

1 × 3 = 3

<h3>step 3. find 36 divided by 2</h3>

36 ÷ 2 = 18

<h3>step 4. add the values together</h3>

18 + 3 = 21

<h3>step 5. find 14 times 3</h3>

14 × 3 = 42 <em>you can also do 7 × 6 and will get the same result because 7 is half of 14 and 3 is half of 6</em>

<h3>step 6. add what is outside the parentheses</h3>

21 + 42 = 63

<h3>step 7. divide by 6</h3>

63 ÷ 6 = 10.5 $-- >$ 10 remainder of 3 <em>remainder means left over</em>

<em />

7 0

2 years ago