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yawa3891 [41]
3 years ago
9

If a golf ball is swinging on a pendulum on the planet mars (g=3.711 m/s²) and it takes 7 seconds to complete one oscillation, w

hat is the approximate length of the pendulum?
Physics
1 answer:
sertanlavr [38]3 years ago
4 0
T = 2*pi*Sqrt (L/g)

T = Period = Time to complete one oscillation, L = Length of the pendulum, g = gravitational acceleration.

Then,

L = {T/(2*pi)}^2*g = {7/(2*pi)}^2*3.711 = 4.606 m
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As a result of the violent revolts in france in july 1830 gave up the throne and fled for Great Britain.

Explanation:

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mamaluj [8]

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Option D

4200 W

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8 0
3 years ago
A shell is fired at an angle of 35° above the horizontal at a velocity of 40 m/s. (a) What is it's speed at the highest point of
Fudgin [204]

Answer:

Part a)

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Part b)

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Explanation:

Part a)

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so here we have

v_x = 40 cos35 = 32.77 m/s

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Part b)

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so we have

\Delta y = 0

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7 0
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