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yawa3891 [41]
3 years ago
9

If a golf ball is swinging on a pendulum on the planet mars (g=3.711 m/s²) and it takes 7 seconds to complete one oscillation, w

hat is the approximate length of the pendulum?
Physics
1 answer:
sertanlavr [38]3 years ago
4 0
T = 2*pi*Sqrt (L/g)

T = Period = Time to complete one oscillation, L = Length of the pendulum, g = gravitational acceleration.

Then,

L = {T/(2*pi)}^2*g = {7/(2*pi)}^2*3.711 = 4.606 m
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Answer:

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First divide both sides by ½

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A' = A/√2

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A' = 0.05840702012600882

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Frequency after split = 6.25Hz (approximated)

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