Answer:
Heat required to melt 1 lb of ice is 151.469 KJ
Explanation:
We have given mass of ice = 1 lb
We know that 1 lb = 0.4535 kg
Latent heat of fusion for ice =334 KJ/kg
Amount if heat for fusion of ice is given by
, here m is mass of ice and L is latent heat of fusion
So heat
So heat required to melt 1 lb of ice is equal to 151.469 KJ
Answer:
The energy in one kilowatt-hour is
Explanation:
Given that,
Power = 1 kW
Time = 1 hour
One kilowatt-hour (kWh) is the amount of work or energy generated when one kilowatt of power is supplied for a time of one hour
We need to calculate the energy
Using formula of energy
Where, P = power
t = time
Put the value into the formula
Hence, The energy in one kilowatt-hour is
Answer:
Explanation:
From the question we are told that:
Period of spring
Initial Position of Mass
Final Mass period
Generally the equation for the Mass location is mathematically given by